用flag法

flag = True
for i in range(3):
    for j in range(3):
        for k in range(3):
            if i == j == k == 1:
                flag = False
                print('break')
                break
        if not flag:
            break
    if not flag:
        break

用循环的else分支

for i in range(3):
    for j in range(3):
        for k in range(3):
            print(i, j, k)
            if i == j == k == 1:
                print('break')
                break
        else:
            continue
        break
    else:
        continue
    break

打包进函数

def loop():
    for i in range(3):
        for j in range(3):
            for k in range(3):
                print(i, j, k)
                if i == j == k == 1:
                    print('break')
                    return

loop()

抛出异常

class Break(Exception):
    pass

try:
    for i in range(3):
        for j in range(3):
            for k in range(3):
                print(i, j, k)
                if i == j == k == 1:
                    raise Break('break')
except Break as e:
    print(e)

最后

以上就是爱笑眼神最近收集整理的关于三进制递增计数，从000~222，循环到111退出用flag法用循环的else分支打包进函数抛出异常的全部内容，更多相关三进制递增计数，从000~222，循环到111退出用flag法用循环内容请搜索靠谱客的其他文章。