题目描述

Taken from 2015 midterm question 4

See mt2015_q4a and mt2015_q4b for the submodules used here. The top-level design consists of two instantiations each of subcircuits A and B, as shown below.

代码

// 解法一：不分层
module top_module (input x, input y, output z);
    
    wire z1,z2,z3,z4;
    assign z1 = (x^y)&x;
    assign z2 = x^~y;
    assign z3 = (x^y)&x;
    assign z4 = x^~y;
    
    assign z = (z1|z2)^(z3&z4);

endmodule

// 解法二：分层
module top_module(
	input x,
	input y,
	output z);

	wire z1, z2, z3, z4;
	
	A ia1 (x, y, z1);
	B ib1 (x, y, z2);
	A ia2 (x, y, z3);
	B ib2 (x, y, z4);
	
	assign z = (z1 | z2) ^ (z3 & z4);

	// Or you could simplify the circuit including the sub-modules:
	// assign z = x|~y;
	
endmodule

module A (
	input x,
	input y,
	output z);

	assign z = (x^y) & x;
	
endmodule

module B (
	input x,
	input y,
	output z);

	assign z = ~(x^y);

endmodule

结果

最后

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