【PAT甲级A1001 】A+B Format (20分)（c++）

1001 A+B Format (20分)

作者：CHEN, Yue
单位：浙江大学
代码长度限制：16 KB
时间限制：400 ms
内存限制：64 MB

Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −10 ^6≤a,b≤10 ^6. The numbers are separated by a space.

Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

题意：

输入两个数，将两数之和表示为标准模式，即每个千位加个逗号。

思路：

需要将数字转换成字符串，应用到stl中to_string函数，正负加以区分，避免出现-,999这样的输出。

参考代码：

#include <iostream>
#include <string>
using namespace std;
int main() {
    int a,b;
    cin>>a>>b;
    string str=to_string(a+b);
    int len=str.length();
    if(str[0]=='-'){
        for(int pos=len-3;pos>1;pos-=3){
            str.insert(pos,",");
        }
    }
    else{
        for(int pos=len-3;pos>0;pos-=3){
            str.insert(pos,",");
        }
    }
    cout<<str<<endl;
    return 0;
}

如有错误，欢迎指正

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