Codeforces——118A String Task

小声BB

昨天一天写的挺多的，这道1000又给我搞心态了

题干

time limit per test：2 seconds
memory limit per test：256 megabytes
input：standard input
output：standard output

Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:

deletes all the vowels,
inserts a character “.” before each consonant,
replaces all uppercase consonants with corresponding lowercase ones.

Vowels are letters “A”, “O”, “Y”, “E”, “U”, “I”, and the rest are consonants. The program’s input is exactly one string, it should return the output as a single string, resulting after the program’s processing the initial string.

Help Petya cope with this easy task.

Input

The first line represents input string of Petya’s program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive.

Output

Print the resulting string. It is guaranteed that this string is not empty.

Examples

Input
tour

Output
.t.r

Input
Codeforces

Output
.c.d.f.r.c.s

Input
aBAcAba

Output
.b.c.b

分析

这道题就是两个步骤：
1、大写字母转换成小写字母；
2、把带a、o、y、e、u、i的字母去掉，剩下的前面加‘.’
我被搞心态是因为100个字母全加点数组要开到200，真是有够好笑呢~

代码

#include<iostream>
#include<string.h>
using namespace std;
int main()
{
string a;
char b[205];
cin >> a;
int bi = 0;
for(int i = 0;i < a.length();i++)
{
if(a[i] >= 'A' && a[i] <= 'Z')
a[i] = a[i] - 'A' + 'a';
if(a[i] != 'a' && a[i] != 'o' && a[i] != 'y' && a[i] != 'e' && a[i] != 'u' && a[i] != 'i')
{
b[bi++] = '.';
b[bi++] = a[i];
}
}
for(int i = 0;i < bi;i++)
cout<<b[i];
return 0;
}

最后

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