使用BigDecimal转换较长小数时候出现科学计数法的问题

复制代码1 public static String divToString(double v1, double v2, int scale){ 2 if (scale < 0) { 3 throw new IllegalArgumentException( 4 "The scale must be a positive integer or zero"); 5 } 6 BigDecimal b1 = new BigDecimal(Double.toString(v1)); 7 BigDecimal b2 = new BigDecimal(Double.toString(v2)); 8 return b1.divide(b2, scale, BigDecimal.ROUND_HALF_UP).toString(); 9 }

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    public static String divToString(double v1, double v2, int scale){
        if (scale < 0) {
            throw new IllegalArgumentException(
                    "The scale must be a positive integer or zero");
        }
        BigDecimal b1 = new BigDecimal(Double.toString(v1));
        BigDecimal b2 = new BigDecimal(Double.toString(v2));
        return  b1.divide(b2, scale, BigDecimal.ROUND_HALF_UP).toString();
    }

只要将BigDecimal 对象toString()就好。