Problem Description：

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

Input：

Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer. 

Output：

For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer. 

Sample Input：

2

3 5 7 15

6 4 10296 936 1287 792 1 

程序代码：

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#include<stdio.h>
int gcd(int a,int b)
{
	return b?gcd(b,a%b):a;//递归求两个数的最大公约数 
}
int lcm(int a,int b)
{
	return a/gcd(a,b)*b;//这里先除后乘求最小公倍数，更好的避免数据溢出 
}
int main()
{
	int t,n,a,b;
	scanf("%d",&t);
	while(t--)
	{
		scanf("%d",&n);
		scanf("%d",&a);
		for(int i=1;i<n;i++)
		{
			scanf("%d",&b);
			a=lcm(a,b);
		}
		printf("%dn",a);
	}
	return 0;
}

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