1248: Let the Balloon Rise

题目

Description

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges’ favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.
This year, they decide to leave this lovely job to you.
Input

Input contains multiple test cases. Each test case starts with a number N ( 0 < N < = 1000 ) – the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.
A test case with N = 0 terminates the input and this test case is not to be processed.
Output

For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.
Sample Input

5
green
red
blue
red
red
3
pink
orange
pink
0
Sample Output

red
pink

代码块

import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner cn = new Scanner(System.in);
while(cn.hasNext()){
int n = cn.nextInt();
if(n==0) return;
Color[] co = new Color[n];
for(int i =0;i<n;i++){
String str = cn.next();
co[i] = new Color(str,0);
}
for(int i =0;i<n-1;i++){
for(int j =i;j<n;j++){
if(co[i].getName().equals(co[j].getName())){
int z = co[i].getMath();
co[i].setMath(++z);
}
}
}
int max = co[0].getMath();
for(int i =0;i<n;i++){
if(max<co[i].getMath()){
max = co[i].getMath();
}
}
for(int i =0;i<n;i++){
if(co[i].getMath()==max){
System.out.println(co[i].getName());
break;
}
}
}
}
}
class Color{
private String name;
private int math;
public Color(String name, int math) {
super();
this.name = name;
this.math = math;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getMath() {
return math;
}
public void setMath(int math) {
this.math = math;
}
}

最后

以上就是文艺老鼠为你收集整理的1248: Let the Balloon Rise的全部内容，希望文章能够帮你解决1248: Let the Balloon Rise所遇到的程序开发问题。

如果觉得靠谱客网站的内容还不错，欢迎将靠谱客网站推荐给程序员好友。