多校第九场 HDU6682 HDU6685

多校第九场 HDU6682 HDU6685

HDU6682 Rikka with Mista

#include <bits/stdc++.h>
#define ll long long
using namespace std;
int w[50];
struct D{
    ll l, r;
};
vector<D> x, y, A[20], B[20];
void Init(int l, int r, vector<D>& x, ll sum){
    if(l > r){x.push_back({sum, 0}); return; }
    Init(l + 1, r, x, sum);
    Init(l + 1, r, x, sum + w[l]);
}
ll get(vector<D>& A, vector<D>& B, ll lim, int opt){//opt表示是否进位
    ll ans = 0;
    if(opt == 0){
        int now = B.size() - 1;
        for(int i = 0; i < A.size(); i++){
            while(now >= 0 && B[now].r + A[i].r >= lim) now--;
            ans += now + 1;
        }
    }else{
        int now = 0;
        for(int i = A.size() - 1; i >= 0; i--){
            while(now < B.size() && B[now].r + A[i].r < lim) now++;
            ans += B.size() - now;
        }
    }
    return ans;
}
void solve(){
    int n; scanf("%d", &n);
    for(int i = 1; i <= n; i++) scanf("%d", &w[i]);
    int mid = n>>1; x.clear(); y.clear();
    Init(1, mid, x, 0);
    Init(mid + 1, n, y, 0);
    ll ans = 0, base = 1;
    int now1, now2, k0, k1;
    for(int t = 1; t <= 12; t++){
        for(int i = 0; i < 10; i++) A[i].clear(), B[i].clear();
        for(int i = 0; i < x.size(); i++) A[x[i].l % 10].push_back({x[i].l / 10, x[i].r});
        for(int i = 0; i < y.size(); i++) B[y[i].l % 10].push_back({y[i].l / 10, y[i].r});

        for(int i = 0; i < 10; i++){
            k0 = (14 - i) % 10, k1 = (13 - i) % 10;
            ans += get(A[i], B[k0], base, 0) + get(A[i], B[k1], base, 1);
        }
        now1 = now2 = 0;
        for(int i = 0; i < 10; i++){
            ll ex = i * base;
            for(int j = 0; j < A[i].size(); j++) x[now1++] = {A[i][j].l, A[i][j].r + ex};
            for(int j = 0; j < B[i].size(); j++) y[now2++] = {B[i][j].l, B[i][j].r + ex};
        }
        base *= 10;
    }
    printf("%lldn", ans);
}
int main(){
    int T; scanf("%d", &T);
    while(T--) solve();
}

HDU6685 Rikka with Coin

50最多一张

20最多三张

10最多1张

100可能少一张

然后暴力就ok了

#include <bits/stdc++.h>
#define ll long long
#define INF 0x3f3f3f3f
using namespace std;
int a[110];
void solve(){
    int n, ans = INF; scanf("%d", &n);
    bool flag = true;
    for(int i = 1; i <= n; i++) {
        scanf("%d", &a[i]);
        if(a[i] % 10) flag = false;
        a[i] /= 10;
    }
    sort(a + 1, a + 1 + n);
    int Maxdollar = max(1, a[n] / 10);
    if(!flag){ printf("-1n"); return; }
    for(int i = 0; i <= 1; i++)
        for(int j = 0; j <= 3; j++)
            for(int k = 0; k <= 1; k++)
                for(int h = Maxdollar - 1; h <= Maxdollar; h++){
                    bool OK = true;
                    for(int cnt = 1; cnt <= n; cnt++){
                        bool ok = false;
                        for(int x = 0; x <= i; x++)
                            for(int y = 0; y <= j; y++)
                                for(int z = 0; z <= k; z++) {
                                    int r = x * 5 + y * 2 + z;
                                    if (h * 10 + r >= a[cnt] && a[cnt] >= r && (h * 10 + r) % 10 == a[cnt] % 10) ok = true;
                                }
                        if(!ok){OK = false; break;}
                    }
                    if(OK) ans = min(ans, i + j + k + h);
                }
    printf("%dn", ans);
}
int main(){
    int T; scanf("%d", &T);
    while(T--) solve();
}

最后

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