js弹出的对话窗口永远保持居中显示

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我是靠谱客的博主高挑大地，最近开发中收集的这篇文章主要介绍js弹出的对话窗口永远保持居中显示，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

复制代码代码如下:

 
<!DOCTYPE html> 
<html lang="en" xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta charset="utf-8" /> 
<title></title> 
<style type="text/css"> 
.Div_Scroll { 
position:fixed; 
margin:-10px; 
visibility:hidden; 
background-color:#808080; 
opacity:0.6; 
z-index:99; 
} 
.Div_Scroll_Content { 
position:relative; 
margin-top:20%; 
width:inherit; 
height:inherit; 
} 
.Div_AlertWindow { 
margin:auto; 
width:200px; 
height:100px; 
background-color:lightblue; 
border:5px solid #f00; 
} 
</style> 
<script type="text/javascript"> 
window.onload = function () { 
var alertWindow = $("alertParent"); 
alertWindow.style.width = window.screen.availWidth + "px"; 
alertWindow.style.height = window.screen.height + "px"; 
$("Sure").onclick = function () { 
alertWindow.style.visibility = "hidden"; 
} 
} 
function ShowAlert() { 
var alertWindow = $("alertParent"); 
alertWindow.style.visibility = "visible"; 
} 
$ = function (id) { 
return document.getElementById(id); 
} 
</script> 
</head> 
<body> 
<div id="alertParent" class="Div_Scroll"> 
<div class="Div_Scroll_Content"> 
<div id="AlertWindow" class="Div_AlertWindow"> 
<input type="button" id="Sure" value="close alert Dialog..." /> 
</div> 
</div> 
</div> 
<div style="height:1300px; padding-top:200px;" > 
<input id="alertButton" type="button" onclick="ShowAlert();" value="Show alert Dialog..."/> 
</div> 
</body> 
</html> 