CodeForces - 236A Boy or Girl （模拟）水

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CodeForces - 236A

Boy or Girl

Time Limit: 1000MS

Memory Limit: 262144KB

64bit IO Format: %I64d & %I64u

Submit Status

Description

Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.

But yesterday, he came to see "her" in the real world and found out "she" is actually a very strong man! Our hero is very sad and he is too tired to love again now. So he came up with a way to recognize users' genders by their user names.

This is his method: if the number of distinct characters in one's user name is odd, then he is a male, otherwise she is a female. You are given the string that denotes the user name, please help our hero to determine the gender of this user by his method.

Input

The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters.

Output

If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes).

Sample Input

Input

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1
wjmzbmr

Output

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1
CHAT WITH HER!

Input

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1
xiaodao

Output

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1
IGNORE HIM!

Input

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1
sevenkplus

Output

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1
CHAT WITH HER!

Hint

For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!".

Source

Codeforces Round #146 (Div. 2)

//题意：

给你一个字符串s,问这个字符串有几个不同的字符，若是奇数个输出IGNORE HIM!，否则输出CHAT WITH HER!

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#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<iostream>
using namespace std;
int vis[30];
char s[110];
int main()
{
int i,j,l;
while(scanf("%s",s)!=EOF)
{
memset(vis,0,sizeof(vis));
int cnt=0;
l=strlen(s);
for(i=0;i<l;i++)
{
if(!vis[s[i]-'a'])
{
vis[s[i]-'a']=1;
cnt++;
}
}
if(cnt&1)
printf("IGNORE HIM!n");
else
printf("CHAT WITH HER!n");
}
return 0;
}