codeforces 236A Boy or Girl

72 阅读 0 评论 48 点赞

我是靠谱客的博主机智书本，这篇文章主要介绍codeforces 236A Boy or Girl，现在分享给大家，希望可以做个参考。

Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very often and eventually they became a couple in the network.

But yesterday, he came to see "her" in the real world and found out "she" is actually a very strong man! Our hero is very sad and he is too tired to love again now. So he came up with a way to recognize users' genders by their user names.

This is his method: if the number of distinct characters in one's user name is odd, then he is a male, otherwise she is a female. You are given the string that denotes the user name, please help our hero to determine the gender of this user by his method.

Input

The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters.

Output

If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes).

Examples

Input

复制代码

1
wjmzbmr

Output

复制代码

1
CHAT WITH HER!

Input

复制代码

1
xiaodao

Output

复制代码

1
IGNORE HIM!

Input

复制代码

1
sevenkplus

Output

复制代码

1
CHAT WITH HER!

Note

For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m", "z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!".

AC:

#include<bits/stdc++.h>
using namespace std;
int main()
{
    char book[26];
    memset(book,0,sizeof(book));
    char p[110];
    gets(p);
    int len=strlen(p),num=0;
    for(int i=0;i<len;i++)
        book[p[i]-'a']++;
    for(int i=0;i<26;i++)
        if(book[i]>0)
            num++;
    if(num%2)
        printf("IGNORE HIM!n");
    else
        printf("CHAT WITH HER!n");
}