概述
【题目描述】
A sequence a0, a1, …, at - 1 is called increasing if ai - 1 < ai for each i: 0 < i < t.
You are given a sequence b0, b1, …, bn - 1 and a positive integer d. In each move you may choose one element of the given sequence and add d to it. What is the least number of moves required to make the given sequence increasing?
【输入】
The first line of the input contains two integer numbers n and d (2 ≤ n ≤ 2000, 1 ≤ d ≤ 106). The second line contains space separated sequence b0, b1, …, bn - 1 (1 ≤ bi ≤ 106).
【输出】
Output the minimal number of moves needed to make the sequence increasing.
【样例输入】
4 2
1 3 3 2
【样例输出】
3
题目链接:https://codeforces.com/contest/11/problem/A
在原有数列上,对一些数字加若干次d使其递增,求最小次数
代码如下:
#include <iostream>
using namespace std;
static const int MAXN=2000+10;
int a[MAXN];
int n,d;
int main()
{
cin>>n>>d;
for(int i=0;i<n;i++) cin>>a[i];
int cnt=0;
for(int i=1;i<n;i++)
{
if(a[i]>a[i-1]) continue;
int t=(a[i-1]+d-a[i])/d;
cnt+=t;
a[i]+=d*t;
}
cout<<cnt<<endl;
return 0;
}
最后
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