Codeforces——231A Team

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我是靠谱客的博主个性白猫，最近开发中收集的这篇文章主要介绍Codeforces——231A Team，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

小声BB

又回到800了，感觉是很不错的，不过自己代码能力有够弱的，思维也很差，很多特例经常考虑不到

题干

time limit per test：2 seconds
memory limit per test：256 megabytes
input：standard input
output：standard output

One day three best friends Petya, Vasya and Tonya decided to form a team and take part in programming contests. Participants are usually offered several problems during programming contests. Long before the start the friends decided that they will implement a problem if at least two of them are sure about the solution. Otherwise, the friends won’t write the problem’s solution.

This contest offers n problems to the participants. For each problem we know, which friend is sure about the solution. Help the friends find the number of problems for which they will write a solution.

Input

The first input line contains a single integer n (1 ≤ n ≤ 1000) — the number of problems in the contest. Then n lines contain three integers each, each integer is either 0 or 1. If the first number in the line equals 1, then Petya is sure about the problem’s solution, otherwise he isn’t sure. The second number shows Vasya’s view on the solution, the third number shows Tonya’s view. The numbers on the lines are separated by spaces.

Output

Print a single integer — the number of problems the friends will implement on the contest.

Examples

Input
3
1 1 0
1 1 1
1 0 0

Output
2

Input
2
1 0 0
0 1 1

Output
1

Note

In the first sample Petya and Vasya are sure that they know how to solve the first problem and all three of them know how to solve the second problem. That means that they will write solutions for these problems. Only Petya is sure about the solution for the third problem, but that isn’t enough, so the friends won’t take it.

In the second sample the friends will only implement the second problem, as Vasya and Tonya are sure about the solution.

分析

我心目中的送分题没跑了，一点坑都没有很舒服，反正就是个有限行输入，判断和大于1就好

代码

#include<iostream>
using namespace std;

int main()
{
	int a,b,c,sum = 0,n;
	cin >> n;
	while(n--)
	{
		cin >> a >> b >> c;
		if(a + b + c > 1)
			sum++;
	}
	cout << sum;
	return 0;
}