概述
I am trying to multiply a vector(3 by 1) by its transpose(1 by 3). I get a (3 by 3) array but I cannot get its inverse. Any idea why?
import numpy as np
c=array([1, 8, 50])
np.transpose(c[np.newaxis]) * c
array([[ 1, 8, 50],
[ 8, 64, 400],
[ 50, 400, 2500]])
np.linalg.inv(np.transpose(c[np.newaxis]) * c)
Traceback (most recent call last):
File "", line 1, in
File "C:Python26libsite-packagesnumpylinalglinalg.py", line 445, in inv
return wrap(solve(a, identity(a.shape[0], dtype=a.dtype)))
File "C:Python26libsite-packagesnumpylinalglinalg.py", line 328, in solve
raise LinAlgError, 'Singular matrix'
LinAlgError: Singular matrix
解决方案
The matrix you pasted
[[ 1, 8, 50],
[ 8, 64, 400],
[ 50, 400, 2500]]
Has a determinant of zero. This is the definition of a Singular matrix (one for which an inverse does not exist)
最后
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