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I am trying to multiply a vector(3 by 1) by its transpose(1 by 3). I get a (3 by 3) array but I cannot get its inverse. Any idea why?

import numpy as np

c=array([1, 8, 50])

np.transpose(c[np.newaxis]) * c

array([[ 1, 8, 50],

[ 8, 64, 400],

[ 50, 400, 2500]])

np.linalg.inv(np.transpose(c[np.newaxis]) * c)

Traceback (most recent call last):

File "", line 1, in

File "C:Python26libsite-packagesnumpylinalglinalg.py", line 445, in inv

return wrap(solve(a, identity(a.shape[0], dtype=a.dtype)))

File "C:Python26libsite-packagesnumpylinalglinalg.py", line 328, in solve

raise LinAlgError, 'Singular matrix'

LinAlgError: Singular matrix

解决方案

The matrix you pasted

[[ 1, 8, 50],

[ 8, 64, 400],

[ 50, 400, 2500]]

Has a determinant of zero. This is the definition of a Singular matrix (one for which an inverse does not exist)

最后

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