java 写一个方法返回值是Map类型

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我是靠谱客的博主甜美大船，这篇文章主要介绍java 写一个方法返回值是Map类型，现在分享给大家，希望可以做个参考。

写一个方法返回值是Map类型：（通过控制台写进去一行字符,分别统计出其英文字母,空格,数字和其它字符放到对应的list里面，最终把list放到Map里并返回)
最近老遇到问这个问题的人，我觉定写个蠢一点的办法满足一下大家

复制代码

import java.util.*;

public class demo1 {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String arr = in.nextLine();

System.out.println(demo(arr));

}

public static Map<String, List> demo (String arr )
    {
        String[] arrs = arr.split(" ");

Map<String,List> map = new HashMap<>();
        List<String> list1 = new LinkedList<>();
        List<String> list2 = new LinkedList<>();
        List<String> list3 = new LinkedList<>();
        List<String> list4 = new LinkedList<>();
            for (int i=0;i<arr.length();i++){
                if ((arr.charAt(i)>='a'&&arr.charAt(i)<='z')||(arr.charAt(i)>='A'&&arr.charAt(i)<='Z')){
                    Character character = arr.charAt(i);
                    list1.add(character.toString());
                }
                else if ('0'<=arr.charAt(i)&&'9'>=arr.charAt(i)){

Character character = arr.charAt(i);
                    list3.add(character.toString());
                }
                else if (' '==arr.charAt(i)){
                    list2.add(" ");
                }
                else {
                    Character character = arr.charAt(i);
                    list4.add(character.toString());
                }

}

map.put("character",list1);
        map.put("space",list2);
        map.put("other",list4);
        map.put("number",list3);
            return map;
        }

}

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import java.util.*;

public class demo1 {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String arr = in.nextLine();

        System.out.println(demo(arr));

    }

    public static Map<String, List> demo (String arr )
    {
        String[] arrs = arr.split(" ");

        Map<String,List> map = new HashMap<>();
        List<String> list1 = new LinkedList<>();
        List<String> list2 = new LinkedList<>();
        List<String> list3 = new LinkedList<>();
        List<String> list4 = new LinkedList<>();
            for (int i=0;i<arr.length();i++){
                if ((arr.charAt(i)>='a'&&arr.charAt(i)<='z')||(arr.charAt(i)>='A'&&arr.charAt(i)<='Z')){
                    Character character = arr.charAt(i);
                    list1.add(character.toString());
                }
                else if ('0'<=arr.charAt(i)&&'9'>=arr.charAt(i)){

                    Character character = arr.charAt(i);
                    list3.add(character.toString());
                }
                else if (' '==arr.charAt(i)){
                    list2.add(" ");
                }
                else {
                    Character character = arr.charAt(i);
                    list4.add(character.toString());
                }

            }




        map.put("character",list1);
        map.put("space",list2);
        map.put("other",list4);
        map.put("number",list3);
            return map;
        }


}