Python求算数平方根和约数的方法汇总

1
2
3
4
5
6
7
8
9
10
11
a=
x=int(raw_input('Enter a number:'))
if x >= :
while a*a < x:
a = a + 
if a*a != x:
print x,'is not a perfect square'
else:
print a
else:
print x,'is a negative number'

1
2
3
4
5
6
7
8
divisor = [ ]
x=int(raw_input('Enter a number:'))
i= 
while i<=x: 
if x%i ==:
divisor.append(i)
i = i +
print 'divisor:',divisor

1
2
3
4
5
6
divisor = [ ]
x=int(raw_input('Enter a number:'))
for i in range(,x+):
if x%i ==:
divisor.append(i) # 此行也可以换成 divisor = divisor + [i]
print 'divisor:',divisor

1
2
import math
math.sqrt( x )

1
2
3
4
5
#!/usr/bin/python
import math # This will import math module
print "math.sqrt(100) : ", math.sqrt(100)
print "math.sqrt(7) : ", math.sqrt(7)
print "math.sqrt(math.pi) : ", math.sqrt(math.pi)

1
2
3
math.sqrt(100) : 10.0
math.sqrt(7) : 2.64575131106
math.sqrt(math.pi) : 1.77245385091