HDU 2057 A + B Again

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我是靠谱客的博主懦弱唇彩，最近开发中收集的这篇文章主要介绍HDU 2057 A + B Again，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

Output

For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input

   +A -A +1A 12 1A -9 -1A -12 1A -AA 
 

Sample Output

   0 2C 11 -2C -90 
 

Author

linle

Source

校庆杯Warm Up

思路：16进制输入输出，注意“The length of A and B is less than 15. ” ，也就是说，数据范围不在int里面，要用long long。

代码：

#include<stdio.h>
int main()
{
    int a,b,res;
    while(~scanf("%llX %llX",&a,&b))
    {
        if(a+b>=0)
            printf("%llXn",a+b);//如果是小写的x的话，也会wa
        else
            printf("-%llXn",-a-b);
    }
    return 0;
}