lamber表达式sql_sql语句-linq语言-lambda表达式对照

1、 查询Student表中的所有记录的Sname、Ssex和Class列。select

sname,ssex,class from student

Linq:

from s

in Students

select new {

s.SNAME,

s.SSEX,

s.CLASS

}Lambda:

Students.Select( s => new {

SNAME = s.SNAME,SSEX = s.SSEX,CLASS = s.CLASS

})

2、查询教师所有的单位即不重复的Depart列。select

distinct depart from teacher

Linq:

from t

in Teachers.Distinct()

select t.DEPARTLambda:

Teachers.Distinct().Select( t =>

t.DEPART)

3、查询Student表的所有记录。select *

from student

Linq:

from s in Students

select sLambda:

Students.Select( s => s)

4、查询Score表中成绩在60到80之间的所有记录。select *

from score where degree between 60 and 80

Linq:

from s in Scores

where s.DEGREE >=

60 && s.DEGREE < 80

select s

Lambda:

Scores.Where(

s =>

(

s.DEGREE >= 60 && s.DEGREE < 80

)

)

5、查询Score表中成绩为85，86或88的记录。select *

from score where degree in (85,86,88)Linq:

In

from s in Scores

where

(

new decimal[]{85,86,88}

).Contains(s.DEGREE)

select sLambda:

Scores.Where( s => new Decimal[]

{85,86,88}.Contains(s.DEGREE))Not

in

from s in Scores

where !(

new

decimal[]{85,86,88}

).Contains(s.DEGREE)

select

sLambda:

Scores.Where( s =>

!(new Decimal[]{85,86,88}.Contains(s.DEGREE)))

Any()应用：双表进行Any时，必须是主键为(String)

CustomerDemographics

CustomerTypeID(String)CustomerCustomerDemos (CustomerID

CustomerTypeID) (String)一个主键与二个主建进行Any(或者是一对一关键进行Any)不可，以二个主键于与一个主键进行Any

from e in

CustomerDemographics

where !e.CustomerCustomerDemos.Any()

select

e

from c in Categories

where !c.Products.Any()

select c

6、查询Student表中"95031"班或性别为"女"的同学记录。select *

from student where class ='95031' or ssex= N'女'Linq:

from s in Students

where s.CLASS == "95031"

|| s.CLASS ==

"女"

select sLambda:

Students.Where(s => ( s.CLASS == "95031" || s.CLASS == "女"))

7、以Class降序查询Student表的所有记录。select *

from student order by Class DESCLinq:

from s in Students

orderby s.CLASS

descending

select sLambda:

Students.OrderByDescending(s => s.CLASS)

8、以Cno升序、Degree降序查询Score表的所有记录。select *

from score order by Cno ASC,Degree DESCLinq:(这里Cno ASC在linq中要写在最外面)

from s in Scores

orderby

s.DEGREE descending

orderby s.CNO ascending

select

sLambda:

Scores.OrderByDescending( s => s.DEGREE)

.OrderBy( s =>

s.CNO)

9、查询"95031"班的学生人数。select

count(*) from student where class = '95031'Linq:

(    from s in Students

where

s.CLASS == "95031"

select s

).Count()Lambda:

Students.Where( s => s.CLASS == "95031"

)

.Select( s => s)

.Count()

10、查询Score表中的最高分的学生学号和课程号。select

distinct s.Sno,c.Cno from student as s,course as c ,score as sc

where

s.sno=(select sno from score where degree = (select max(degree) from

score))

and c.cno = (select cno from score where degree = (select max(degree)

from score))Linq:

(

from s in Students

from c in Courses

from sc in

Scores

let maxDegree = (from sss in Scores

select sss.DEGREE

).Max()

let sno = (from

ss in Scores

where ss.DEGREE == maxDegree

select ss.SNO).Single().ToString()

let cno = (from ssss in

Scores

where ssss.DEGREE == maxDegree

select ssss.CNO).Single().ToString()

where s.SNO == sno &&

c.CNO == cno

select new {

s.SNO,

c.CNO

}

).Distinct()操作时问题？执行时报错：where s.SNO == sno(这行报出来的) 运算符"=="无法应用于"string"和"System.Linq.IQueryable"类型的操作数解决：原：let

sno = (from ss in Scores

where ss.DEGREE ==

maxDegree

select

ss.SNO).ToString()

Queryable().Single()返回序列的唯一元素；如果该序列并非恰好包含一个元素，则会引发异常。解：let

sno = (from ss in Scores

where ss.DEGREE ==

maxDegree

select

ss.SNO).Single().ToString()

11、查询'3-105'号课程的平均分。select

avg(degree) from score where cno = '3-105'

Linq:

(

from s in Scores

where s.CNO == "3-105"

select s.DEGREE

).Average()Lambda:

Scores.Where(

s => s.CNO == "3-105")

.Select( s =>

s.DEGREE)

.Average()

12、查询Score表中至少有5名学生选修的并以3开头的课程的平均分数。select

avg(degree) from score where cno like '3%' group by Cno having

count(*)>=5

Linq:

from s in

Scores

where s.CNO.StartsWith("3")

group s by

s.CNO

into cc

where cc.Count() >= 5

select

cc.Average( c => c.DEGREE)Lambda:

Scores.Where( s =>

s.CNO.StartsWith("3") )

.GroupBy( s => s.CNO

)

.Where( cc => ( cc.Count() >= 5) )

.Select( cc => cc.Average( c => c.DEGREE) )Linq: SqlMethod

like也可以这样写:

s.CNO.StartsWith("3")

or SqlMethods.Like(s.CNO,"%3")

13、查询最低分大于70，最高分小于90的Sno列。select sno

from score group by sno having min(degree) > 70 and max(degree) <

90Linq:

from s in Scores

group s by s.SNO

into ss

where ss.Min(cc => cc.DEGREE) > 70

&& ss.Max( cc => cc.DEGREE) < 90

select new

{

sno = ss.Key

}Lambda:

Scores.GroupBy (s =>

s.SNO)

.Where (ss => ((ss.Min (cc => cc.DEGREE) > 70)

&& (ss.Max (cc => cc.DEGREE) < 90)))

.Select

( ss => new {

sno =

ss.Key

})

14、查询所有学生的Sname、Cno和Degree列。select

s.sname,sc.cno,sc.degree from student as s,score as sc where s.sno =

sc.snoLinq:

from s in

Students

join sc in Scores

on s.SNO equals sc.SNO

select

new

{

s.SNAME,

sc.CNO,

sc.DEGREE

}Lambda:

Students.Join(Scores, s

=> s.SNO,

sc => sc.SNO,

(s,sc) =>

new{

SNAME =

s.SNAME,

CNO =

sc.CNO,

DEGREE =

sc.DEGREE

})

15、查询所有学生的Sno、Cname和Degree列。select

sc.sno,c.cname,sc.degree from course as c,score as sc where c.cno =

sc.cnoLinq:

from c in

Courses

join sc in Scores

on c.CNO equals sc.CNO

select

new

{

sc.SNO,c.CNAME,sc.DEGREE

}Lambda:

Courses.Join ( Scores, c => c.CNO,

sc => sc.CNO,

(c, sc) => new

{

SNO = sc.SNO,

CNAME = c.CNAME,

DEGREE =

sc.DEGREE

})

16、查询所有学生的Sname、Cname和Degree列。select

s.sname,c.cname,sc.degree from student as s,course as c,score as sc where s.sno

= sc.sno and c.cno = sc.cnoLinq:

from s in Students

from c in Courses

from sc in Scores

where s.SNO == sc.SNO && c.CNO == sc.CNO

select new {

s.SNAME,c.CNAME,sc.DEGREE }