实现同时只允许运行一个程序实例

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我是靠谱客的博主痴情短靴，最近开发中收集的这篇文章主要介绍实现同时只允许运行一个程序实例，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

方法一:

/// <summary>
/// 从这里开始运行
/// </summary>
[STAThread]
static void Main()
{
    Process instance = RunningInstance();
    if (instance == null)
    {
        //没有实例在运行
        WeatherApp appInstance = new WeatherApp();
        appInstance.StartMainGui();
    }
    else
    {
        //已经有一个实例在运行
        HandleRunningInstance(instance);
    }
}
#region 确保只有一个实例
public static Process RunningInstance()
{
    Process current = Process.GetCurrentProcess();
    Process[] processes = Process.GetProcessesByName(current.ProcessName);
    //遍历与当前进程名称相同的进程列表
    foreach (Process process in processes)
    {
        //Ignore the current process
        if (process.Id != current.Id)
        {
            //Make sure that the process is running from the exe file.
            if (Assembly.GetExecutingAssembly().Location.Replace("/", "//") == current.MainModule.FileName)
            {
                //Return the other process instance.
                return process;
            }
        }
    }
    return null;
}
private static void HandleRunningInstance(Process instance)
{
    MessageBox.Show("该应用系统已经在运行！", "提示信息", MessageBoxButtons.OK, MessageBoxIcon.Information);
    ShowWindowAsync(instance.MainWindowHandle, 1); //调用api函数，正常显示窗口
    SetForegroundWindow(instance.MainWindowHandle); //将窗口放置最前端。
}
[DllImport("User32.dll")]
private static extern bool ShowWindowAsync(System.IntPtr hWnd, int cmdShow);
[DllImport("User32.dll")]
private static extern bool SetForegroundWindow(System.IntPtr hWnd);
#endregion

方法二:

[STAThread]
static void Main(string[] args)
{
    bool isFirst;

    System.Threading.Mutex mutex = new System.Threading.Mutex(true, "WindowAppTest", out isFirst);
    //这里的myApp是程序的标识,建议换成你的程序的物理路径,这样的话如果在一个操作系统中这个标志不会和其它程序冲突
    if (!isFirst)
    {
        MessageBox.Show("Exist");
        Environment.Exit(1);//实例已经存在,退出程序
    }
    else
    {
        Application.Run(new Form1());
    }
}