概述
Given a string, sort it in decreasing order based on the frequency of characters.
Example 1:
Input:
"tree"
Output:
"eert"
Explanation:
'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Therefore "eetr" is also a valid answer.
Example 2:
Input:
"cccaaa"
Output:
"cccaaa"
Explanation:
Both 'c' and 'a' appear three times, so "aaaccc" is also a valid answer. Note that "cacaca" is incorrect, as the same characters must be together.
Example 3:
Input:
"Aabb"
Output:
"bbAa"
Explanation:
"bbaA" is also a valid answer, but "Aabb" is incorrect. Note that 'A' and 'a' are treated as two different characters.
题意:
对于一个给定的字符串,将字符按照所出现的次数降序排列
思路:
可以考虑先进行字符统计,然后再降序排列
import collections class Solution: def frequencySort(self, s): return ''.join(c * t for c, t in collections.Counter(s).most_common())
提示:
在Python中,collections模块下的Counter类(计数器)是一个容器,用来跟踪值出现的次数,是字典dict的子类,用来为hashtable对象计数。
转载于:https://www.cnblogs.com/yancea/p/7908564.html
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