我是靠谱客的博主 醉熏云朵,最近开发中收集的这篇文章主要介绍451.Sort Characters By Frequency(Medium),觉得挺不错的,现在分享给大家,希望可以做个参考。

概述

Given a string, sort it in decreasing order based on the frequency of characters.

Example 1:

Input:
"tree"

Output:
"eert"

Explanation:
'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Therefore "eetr" is also a valid answer. 

Example 2:

Input:
"cccaaa"

Output:
"cccaaa"

Explanation:
Both 'c' and 'a' appear three times, so "aaaccc" is also a valid answer. Note that "cacaca" is incorrect, as the same characters must be together. 

Example 3:

Input:
"Aabb"

Output:
"bbAa"

Explanation:
"bbaA" is also a valid answer, but "Aabb" is incorrect. Note that 'A' and 'a' are treated as two different characters.

题意:
对于一个给定的字符串,将字符按照所出现的次数降序排列

思路:
可以考虑先进行字符统计,然后再降序排列

import collections

class Solution:
    def frequencySort(self, s):
        return ''.join(c * t for c, t in collections.Counter(s).most_common())

提示:

在Python中,collections模块下的Counter类(计数器)是一个容器,用来跟踪值出现的次数,是字典dict的子类,用来为hashtable对象计数。

 

转载于:https://www.cnblogs.com/yancea/p/7908564.html

最后

以上就是醉熏云朵为你收集整理的451.Sort Characters By Frequency(Medium)的全部内容,希望文章能够帮你解决451.Sort Characters By Frequency(Medium)所遇到的程序开发问题。

如果觉得靠谱客网站的内容还不错,欢迎将靠谱客网站推荐给程序员好友。

本图文内容来源于网友提供,作为学习参考使用,或来自网络收集整理,版权属于原作者所有。
点赞(45)

评论列表共有 0 条评论

立即
投稿
返回
顶部