概述
前言
Django附带的认证对于大多数常见情况来说已经足够了,但是如何在 Django 中使用自定义的数据表进行用户认证,有一种较为笨蛋的办法就是自定义好数据表后,使用OnetoOne来跟 Django 的表进行关联,类似于这样:
from django.contrib.auth.models import User class UserProfile(models.Model): """ 用户账号表 """ user = models.OneToOneField(User) name = models.CharField(max_length=32) def __str__(self): return self.name class Meta: verbose_name_plural = verbose_name = "用户账号" ordering = ['id']
这样做虽然可以简单、快速的实现,但是有一个问题就是我们在自己的表中创建一个用户就必须再跟 admin 中的一个用户进行关联,这简直是不可以忍受的。
admin代替默认User model
写我们自定义的 models 类来创建用户数据表来代替默认的User model,而不与django admin的进行关联,相关的官方文档在这里
👾戳我
from django.db import models from django.contrib.auth.models import User from django.contrib.auth.models import ( BaseUserManager, AbstractBaseUser ) class UserProfileManager(BaseUserManager): def create_user(self, email, name, password=None): """ 用户创建,需要提供 email、name、password """ if not email: raise ValueError('Users must have an email address') user = self.model( email=self.normalize_email(email), name=name, ) user.set_password(password) user.save(using=self._db) return user def create_superuser(self, email, name, password): """ 超级用户创建,需要提供 email、name、password """ user = self.create_user( email, password=password, name=name, ) user.is_admin = True user.is_active = True user.save(using=self._db) return user class UserProfile(AbstractBaseUser): # 在此处可以配置更多的自定义字段 email = models.EmailField( verbose_name='email address', max_length=255, unique=True, ) name = models.CharField(max_length=32, verbose_name="用户名称") phone = models.IntegerField("电话") is_active = models.BooleanField(default=True) is_admin = models.BooleanField(default=False) objects = UserProfileManager() USERNAME_FIELD = 'email' # 将email 作为登入用户名 REQUIRED_FIELDS = ['name', 'phone'] def __str__(self): return self.email def get_full_name(self): # The user is identified by their email address return self.email def get_short_name(self): # The user is identified by their email address return self.email def has_perm(self, perm, obj=None): "Does the user have a specific permission?" # Simplest possible answer: Yes, always return True def has_module_perms(self, app_label): "Does the user have permissions to view the app `app_label`?" # Simplest possible answer: Yes, always return True @property def is_staff(self): "Is the user a member of staff?" # Simplest possible answer: All admins are staff return self.is_admin
admin 配置
class UserCreationForm(forms.ModelForm): """A form for creating new users. Includes all the required fields, plus a repeated password.""" password1 = forms.CharField(label='Password', widget=forms.PasswordInput) password2 = forms.CharField(label='Password confirmation', widget=forms.PasswordInput) class Meta: model = models.UserProfile fields = ('email', 'name') def clean_password2(self): password1 = self.cleaned_data.get("password1") password2 = self.cleaned_data.get("password2") if password1 and password2 and password1 != password2: raise forms.ValidationError("Passwords don't match") return password2 def save(self, commit=True): user = super(UserCreationForm, self).save(commit=False) user.set_password(self.cleaned_data["password1"]) if commit: user.save() return user class UserChangeForm(forms.ModelForm): """A form for updating users. Includes all the fields on the user, but replaces the password field with admin's password hash display field. """ password = ReadOnlyPasswordHashField() class Meta: model = models.UserProfile fields = ('email', 'password', 'name', 'is_active', 'is_admin') def clean_password(self): return self.initial["password"] class UserProfileAdmin(BaseUserAdmin): form = UserChangeForm add_form = UserCreationForm list_display = ('email', 'name', 'is_admin', 'is_staff') list_filter = ('is_admin',) fieldsets = ( (None, {'fields': ('email', 'password')}), ('Personal info', {'fields': ('name',)}), ('Permissions', {'fields': ('is_admin', 'is_active', 'roles', 'user_permissions', 'groups')}), ) add_fieldsets = ( (None, { 'classes': ('wide',), 'fields': ('email', 'name', 'password1', 'password2')} ), ) search_fields = ('email',) ordering = ('email',) filter_horizontal = ('groups', 'user_permissions','roles')
2.Django允许您通过AUTH_USER_MODEL配置来引用自定义的model设置来覆盖默认User模型,这个配置的配置方法为在 settings 中加入:AUTH_USER_MODEL = "APP.model_class"
,例如本例中我们需要在 setting 中加入以下配置:
AUTH_USER_MODEL = "app1.UserProfile"
3.部署
python manage.py makemigrations python manage.py migrate
创建一个新用户,此时我们就可以用这个用户来登录 admin 后台了
python manage.py createsuperuser
效果如下:
自定义认证
那如果我们需要使用我们自己的认证系统呢,假如我们有一个 login 页面和一个 home 页面:
from django.shortcuts import render, HttpResponse, redirect from django.contrib.auth import authenticate,login,logout from app1 import models from django.contrib.auth.decorators import login_required def auth_required(auth_type): # 认证装饰器 def wapper(func): def inner(request, *args, **kwargs): if auth_type == 'admin': ck = request.COOKIES.get("login") # 获取当前登录的用户 if request.user.is_authenticated() and ck: return func(request, *args, **kwargs) else: return redirect("/app1/login/") return inner return wapper def login_auth(request): # 认证 if request.method == "GET": return render(request, 'login.html') elif request.method == "POST": username = request.POST.get('username', None) password = request.POST.get('password', None) user = authenticate(username=username, password=password) if user is not None: if user.is_active: login(request, user) _next = request.GET.get("next",'/crm') return redirect('_next') else: return redirect('/app1/login/') else: return redirect('/app1/login/') else: pass def my_logout(request): # 注销 if request.method == 'GET': logout(request) return redirect('/app1/login/') @login_required def home(request): # home page path1, path2 = "Home", '主页' if request.method == "GET": return render(request, 'home.html', locals()) elif request.method == "POST": pass
总结
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最后
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