VINS-Fusion代码按执行顺序阅读(二)
main()函数的最后一句,std::thread sync_thread{sync_process};可以看出,只有time0在time1前后0.03s内的两幅图片,才会被发布estimator.inputImage(time, image0, image1);。// extract images with same timestamp from two topicsvoid sync_p...