codeforces 474A Keyboard

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我是靠谱客的博主背后糖豆，最近开发中收集的这篇文章主要介绍codeforces 474A Keyboard，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

Our good friend Mole is trying to code a big message. He is typing on an unusual keyboard with characters arranged in following way:

qwertyuiop
asdfghjkl;
zxcvbnm,./

Unfortunately Mole is blind, so sometimes it is problem for him to put his hands accurately. He accidentally moved both his hands with one position to the left or to the right. That means that now he presses not a button he wants, but one neighboring button (left or right, as specified in input).

We have a sequence of characters he has typed and we want to find the original message.

Input

First line of the input contains one letter describing direction of shifting ('L' or 'R' respectively for left or right).

Second line contains a sequence of characters written by Mole. The size of this sequence will be no more than 100. Sequence contains only symbols that appear on Mole's keyboard. It doesn't contain spaces as there is no space on Mole's keyboard.

It is guaranteed that even though Mole hands are moved, he is still pressing buttons on keyboard and not hitting outside it.

Output

Print a line that contains the original message.

Examples

Input

R
s;;upimrrfod;pbr

Output

allyouneedislove

AC:

#include<bits/stdc++.h>
using namespace std;
int main()
{
char a[]="qwertyuiop[]\asdfghjkl;'zxcvbnm,./";
char ch;
//|这儿对转义字符的注意要记住
scanf("%c",&ch);
char p[110];
scanf("%s",p);
if(ch=='R')
{
for(int j=0;j<strlen(p);j++)
{
for(int i=0;i<34;i++)
{
if(p[j]-a[i]==0)
{
cout<<a[i-1];
break;
}
}
}
}
if(ch=='L')
{
for(int j=0;j<strlen(p);j++)
{
for(int i=0;i<34;i++)
{
if(p[j]-a[i]==0)
{
cout<<a[i+1];
break;
}
}
}
}
}