codeforce#362B. Barnicle(java高精度类)

codeofrce:http://codeforces.com/contest/697/problem/B

qduoj:https://qduoj.com/problem/120/

将科学计数法表示的数字转化为一般数字

Java的高精度类：

import java.util.Scanner;
public class Main {
static Scanner sc = new Scanner(System.in);
public static void main(String[] args) {
System.out.println(sc.nextBigDecimal().stripTrailingZeros().toPlainString());
}
}

#include<iostream>
#include<algorithm>
#include<cstring>
#include<string>
#include<cstdio>
#include<vector>
#include<queue>
#include<set>
#include<map>
using namespace std;
int main()
{
string p, num, q, first, last;
while(cin >> p)
{
int len = p.length();
int e = p.find_first_of('e'), n = 0;
int point = p.find_first_of('.');
num = p.substr(0, e);
q = p.substr(e+1, len - e);
for(int i = 0; i < q.length(); i++)
n = n*10 + q[i] - '0';
first = p.substr(0, point);
last = p.substr(point+1, e-point-1);
if(first.length() == 1 && first[0] == '0' && last.find_first_not_of('0') >= last.length())
{
cout << 0 << endl;
continue;
}
if(last.find_first_not_of('0') >= last.length())
{
cout << first;
for(int i = 0; i < n; i++)
cout<<0;
cout << endl;
continue;
}
if(first.length() == 1 && first[0] == '0' )
{
if(n == 0)
{
cout << 0 << "." << last << endl;
continue;
}
if(last.length() > n)
{
string ans = last.substr(0, n);
int flag = 0;
if(ans.find_first_not_of('0') >= ans.length())
cout << 0;
else
{
for(int k = 0; k < ans.length(); k++)
{
if(ans[k] == '0' && flag == 0)
continue;
else
{
flag = 1;
cout << ans[k];
}
}
}
cout
<<"."<<last.substr(n, last.length()) << endl;
}
else
{
cout << last;
for(int i = 0; i < n-last.length(); i++)
cout << 0;
cout << endl;
}
continue;
}
else
{
if(n == 0)
{
cout << first << "." << last << endl;
continue;
}
if(last.length() > n)
{
cout << first << last.substr(0, n) <<"."<<last.substr(n, last.length()) << endl;
}
else
{
cout << first << last;
for(int i = 0; i < n-last.length(); i++)
cout << 0;
cout << endl;
}
continue;
}
}
return 0;
}

最后

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