input joystick keyevent 109报错Error: Invalid arguments for command: keyevent平台问题原因解决方法详细内容总结

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平台

Android 5.1

问题

由于没有手柄，用命令模拟手柄按键，但是报错Error: Invalid arguments for command: keyevent，确认格式是按照Usage中说明的格式：

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130|root:/ # input joystick keyevent 109
Error: Invalid arguments for command: keyevent
Usage: input [<source>] <command> [<arg>...]
The sources are:
mouse
keyboard
joystick
touchnavigation
touchpad
trackball
stylus
dpad
touchscreen
gamepad
The commands and default sources are:
text <string> (Default: touchscreen)
keyevent [--longpress] <key code number or name> ... (Default: keyboard)
tap <x> <y> (Default: touchscreen)
swipe <x1> <y1> <x2> <y2> [duration(ms)] (Default: touchscreen)
press (Default: trackball)
roll <dx> <dy> (Default: trackball)

原因

5.1的Input.java中，处理keyevent类型的command时做了一个判断，该判断的逻辑有误（对比Android 10），导致只有一个arg时直接走到参数错误的逻辑

解决方法

由于和处理的问题本身无关，所以没有修改Input.java，若要修改可以参考Android 10的Input.java（下文详细说明）。不修改的话，输入模拟按键命令的时候可以多加一次目标键值，如：input joystick keyevent 109 109

详细内容

input命令

input命令其实很简单，输入错误的input命令（input -h等随便什么）查看使用方式：

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Usage: input [<source>] <command> [<arg>...]
The sources are:
mouse
keyboard
joystick
touchnavigation
touchpad
trackball
stylus
dpad
touchscreen
gamepad
The commands and default sources are:
text <string> (Default: touchscreen)
keyevent [--longpress] <key code number or name> ... (Default: keyboard)
tap <x> <y> (Default: touchscreen)
swipe <x1> <y1> <x2> <y2> [duration(ms)] (Default: touchscreen)
press (Default: trackball)
roll <dx> <dy> (Default: trackball)

可以看到完整的input命令source+command+arg，source就是模拟的是什么设备，command就是模拟的输入方式，arg就是具体的参数了，模拟手柄按键时，source为joystick，command为keyevent，后面具体键值可以查看KeyEvent.java中定义的。

Input命令处理（keyevent）

处理的逻辑位于/frameworks/base/cmds/input/src/com/android/commands/input/Input.java，针对keyevent类型的command，5.1的处理如下：

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private void run(String[] args) {
//args不包含“input”，从之后算起
if (args.length < 1) {
showUsage();
return;
}
//假设串口输入“input joystick keyevent 109”，args此时是“joystick keyevent 109”
int index = 0;
String command = args[index];
//command = “joystick”
int inputSource = InputDevice.SOURCE_UNKNOWN;
if (SOURCES.containsKey(command)) {
inputSource = SOURCES.get(command);
index++;
//index = 1
command = args[index];
//command = “keyevent”
}
final int length = args.length - index;
//记住这个变量，此时是3-1 = 2
try {
if (command.equals("text")) {
...
} else if (command.equals("keyevent")) {
if (length >= 2) {
//判断是否有长按标志
final boolean longpress = "--longpress".equals(args[index + 1]);
final int start = longpress ? index + 2 : index + 1;
//start = 2
inputSource = getSource(inputSource, InputDevice.SOURCE_KEYBOARD);
//经过上面的步骤，length = 2，start = 2，不仅如此if，直接出try-catch块到
//最后的错误处理
if (length > start) {
for (int i = start; i < length; i++) {
int keyCode = KeyEvent.keyCodeFromString(args[i]);
if (keyCode == KeyEvent.KEYCODE_UNKNOWN) {
keyCode = KeyEvent.keyCodeFromString("KEYCODE_" + args[i]);
}
sendKeyEvent(inputSource, keyCode, longpress);
}
return;
}
}
}
...
} catch (NumberFormatException ex) {
}
System.err.println(INVALID_ARGUMENTS + command);
showUsage();
}

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private void run(String[] args) {
//args不包含“input”，从之后算起
if (args.length < 1) {
showUsage();
return;
}
//假设串口输入“input joystick keyevent 109”，args此时是“joystick keyevent 109”
int index = 0;
String command = args[index];
//command = “joystick”
int inputSource = InputDevice.SOURCE_UNKNOWN;
if (SOURCES.containsKey(command)) {
inputSource = SOURCES.get(command);
index++;
//index = 1
command = args[index];
//command = “keyevent”
}
final int length = args.length - index;
//记住这个变量，此时是3-1 = 2
try {
if (command.equals("text")) {
...
} else if (command.equals("keyevent")) {
if (length >= 2) {
//判断是否有长按标志
final boolean longpress = "--longpress".equals(args[index + 1]);
final int start = longpress ? index + 2 : index + 1;
//start = 2
inputSource = getSource(inputSource, InputDevice.SOURCE_KEYBOARD);
//经过上面的步骤，length = 2，start = 2，不仅如此if，直接出try-catch块到
//最后的错误处理
if (length > start) {
for (int i = start; i < length; i++) {
int keyCode = KeyEvent.keyCodeFromString(args[i]);
if (keyCode == KeyEvent.KEYCODE_UNKNOWN) {
keyCode = KeyEvent.keyCodeFromString("KEYCODE_" + args[i]);
}
sendKeyEvent(inputSource, keyCode, longpress);
}
return;
}
}
}
...
} catch (NumberFormatException ex) {
}
System.err.println(INVALID_ARGUMENTS + command);
showUsage();
}

再看Android 10中的处理，明显不一样的地方就是判断是否有长按标志之后的if条件：

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private void run(String[] args) {
if (args.length < 1) {
showUsage();
return;
}
int index = 0;
String command = args[index];
int inputSource = InputDevice.SOURCE_UNKNOWN;
if (SOURCES.containsKey(command)) {
inputSource = SOURCES.get(command);
index++;
command = args[index];
}
final int length = args.length - index;
try {
if (command.equals("text")) {
...
} else if (command.equals("keyevent")) {
if (length >= 2) {
final boolean longpress = "--longpress".equals(args[index + 1]);
final int start = longpress ? index + 2 : index + 1;
inputSource = getSource(inputSource, InputDevice.SOURCE_KEYBOARD);
//注意这里使用的是args.length而不是前面计算的length
//如果是“input joystick keyevent 109”，args.length = 3, start = 2
if (args.length > start) {
for (int i = start; i < args.length; i++) {
int keyCode = KeyEvent.keyCodeFromString(args[i]);
if (keyCode == KeyEvent.KEYCODE_UNKNOWN) {
keyCode = KeyEvent.keyCodeFromString("KEYCODE_" + args[i]);
}
sendKeyEvent(inputSource, keyCode, longpress);
}
return;
}
}
} ...
} catch (NumberFormatException ex) {
}
System.err.println(INVALID_ARGUMENTS + command);
showUsage();
}

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private void run(String[] args) {
if (args.length < 1) {
showUsage();
return;
}
int index = 0;
String command = args[index];
int inputSource = InputDevice.SOURCE_UNKNOWN;
if (SOURCES.containsKey(command)) {
inputSource = SOURCES.get(command);
index++;
command = args[index];
}
final int length = args.length - index;
try {
if (command.equals("text")) {
...
} else if (command.equals("keyevent")) {
if (length >= 2) {
final boolean longpress = "--longpress".equals(args[index + 1]);
final int start = longpress ? index + 2 : index + 1;
inputSource = getSource(inputSource, InputDevice.SOURCE_KEYBOARD);
//注意这里使用的是args.length而不是前面计算的length
//如果是“input joystick keyevent 109”，args.length = 3, start = 2
if (args.length > start) {
for (int i = start; i < args.length; i++) {
int keyCode = KeyEvent.keyCodeFromString(args[i]);
if (keyCode == KeyEvent.KEYCODE_UNKNOWN) {
keyCode = KeyEvent.keyCodeFromString("KEYCODE_" + args[i]);
}
sendKeyEvent(inputSource, keyCode, longpress);
}
return;
}
}
} ...
} catch (NumberFormatException ex) {
}
System.err.println(INVALID_ARGUMENTS + command);
showUsage();
}