Rank Scores

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks.

+----+-------+
| Id | Score |
+----+-------+
| 1  | 3.50  |
| 2  | 3.65  |
| 3  | 4.00  |
| 4  | 3.85  |
| 5  | 4.00  |
| 6  | 3.65  |
+----+-------+

For example, given the above Scores table, your query should generate the following report (order by highest score):

+-------+------+
| Score | Rank |
+-------+------+
| 4.00  | 1    |
| 4.00  | 1    |
| 3.85  | 2    |
| 3.65  | 3    |
| 3.65  | 3    |
| 3.50  | 4    |
+-------+------+

题意：

就是对成绩进行排序，但需要注意的是，相同值的排名相同，而且排名还能有漏掉的排序数。如上表中的3.85是2而不是3

解法一：

# Write your MySQL query statement below
SELECT Scores.Score, COUNT(Ranking.Score) AS RANK
  FROM Scores
     , (
       SELECT DISTINCT Score
         FROM Scores
       ) Ranking
 WHERE Scores.Score <= Ranking.Score
 GROUP BY Scores.Id
 ORDER BY Scores.Score DESC;

解法二

使用MySQL的用户定义变量。

# Write your MySQL query statement below
SELECT Score, Rank FROM(
  SELECT    Score,
            @curRank := @curRank + IF(@prevScore = Score, 0, 1) AS Rank, @prevScore := Score
  FROM      Scores s, (SELECT @curRank := 0) r, (SELECT @prevScore := NULL) p
  ORDER BY  Score DESC
) t;

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