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[Pointers and C-String]D. Liang 7.2 Printing distinct numbers

Description:

Use pointers on array to write a program that reads in n integers and displays distinct numbers (ie., if a number appears multiple times, it is displayed only once).

Input:

The first line is a positive integer t for the number of test cases.
Each test case contains two lines. The first line is an integer n (0<n<=100).
The second line contains n integers.

Output:

For each test case, outputs the distinct numbers in order in which they were read, separated by one blank.

Sample Input:

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2 3 1 2 1 4 2 1 2 1

Sample Output:

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1 2 2 1

Programme:

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//Date:2020/5/8 //Author:Kamenrider Justice #include<stdio.h> int main() { int n,i,j,k,num;//n是运行的次数,num是输入的个数 scanf("%d",&n); int number[100];//储存输入的数 int flag; //判断是否有重复的数 for(i=0;i<n;i++) { scanf("%d",&num); for(j=0;j<num;j++)//储存数到数组 { scanf("%d ",&number[j]); } printf("%d",number[0]); for(j=1;j<num;j++) { flag=1;//使flag回到初始状态 for(k=0;k<j;k++) { if(*(number+j)==*(number+k)) { flag=0; } } if(flag)//如果没有重复的就输出,可保证顺序和输入时一致 { printf(" %d",number[j]); } } printf("n"); } return 0; }

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