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[Pointers and C-String]D. Liang 7.2 Printing distinct numbers
Description:
Use pointers on array to write a program that reads in n integers and displays distinct numbers (ie., if a number appears multiple times, it is displayed only once).
Input:
The first line is a positive integer t for the number of test cases.
Each test case contains two lines. The first line is an integer n (0<n<=100).
The second line contains n integers.
Output:
For each test case, outputs the distinct numbers in order in which they were read, separated by one blank.
Sample Input:
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52 3 1 2 1 4 2 1 2 1
Sample Output:
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21 2 2 1
Programme:
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37//Date:2020/5/8 //Author:Kamenrider Justice #include<stdio.h> int main() { int n,i,j,k,num;//n是运行的次数,num是输入的个数 scanf("%d",&n); int number[100];//储存输入的数 int flag; //判断是否有重复的数 for(i=0;i<n;i++) { scanf("%d",&num); for(j=0;j<num;j++)//储存数到数组 { scanf("%d ",&number[j]); } printf("%d",number[0]); for(j=1;j<num;j++) { flag=1;//使flag回到初始状态 for(k=0;k<j;k++) { if(*(number+j)==*(number+k)) { flag=0; } } if(flag)//如果没有重复的就输出,可保证顺序和输入时一致 { printf(" %d",number[j]); } } printf("n"); } return 0; }
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