Struts1的DispatchAction()方法

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
package com.action;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import org.apache.struts.actions.DispatchAction;
public class UserLogin extends DispatchAction{
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws Exception {
System.out.println("主要的方法");
return super.execute(mapping, form, request, response);
}
public ActionForward Login(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws Exception {
System.out.println("这个是Login");
return mapping.findForward("welcome");
}
}

1
2
3
4
5
6
7
8
9
10
<action-mappings >
<action path="/UserLogin"
name="userForm"
type="com.action.UserLogin"

parameter="action">
<forward name="welcome" path="/welcome.jsp"></forward>
<forward name="error" path="/index.jsp"></forward>
</action>
</action-mappings>

1
 <form action="UserLogin.do?action=Login" method="post"></form>