练习题13-15

# 13有两个列表
# l1 = [11, 22, 33, 44]
# l2 = [66, 77, 22, 33, 44, 55]
# a.获取内容相同的元素列表
# for l3 in l1:
#     for l4 in l2:
#         if l3 == l4:
#             print(l4)
#
# for l3 in l1:
#     if l3 in l2:
#         print(l3)
# b.获取l1中有，l2中没有的元素列表
# for l3 in l1:
#     if l3 in l2:
#         continue
#     else:
#         print(l3)
# c.获取l2中有，l1中没有的元素列表
# for l4 in l2:
#     if l4 not in l1:
#         print(l4)
# d.获取l1和l2中都不同的元素。
# for l3 in l1:
#     for l4 in l2:
#         if l3 == l4:
#             l1.remove(l3)
#             l2.remove(l3)
# print(l1,l2)本题做的有错误，在22比较完删除后，第一个列表里的33索引会自动变成22，而第二个列表里循环还在进行，当遍历完第二个列表，第一个列表的33索引已经占据了原来删除掉的22索引，循环会直接跳过33接着取出44进行遍历比较。本方法修
改如下：

l4=l2.copy()
for l3 in l1:
    if l3 in l2:
        l2.remove(l3)
for i4 in l4:
    if i4 in l1:
        l1.remove(i4)
print(l1,l2)
# 14.利用for循环和range输出。

#
# a.for循环从大到小输出1-100.
# for a in range(1,101):
#     print(a)
# b.for循环从小到大输出100-1
# for a in range(1,101):
#     print(101-a)
# c.wile循环从小到大输出1-100
# a=0
# while a<100:
#     a=a+1
#     print(a)
# d.wile循环从大到小输出100-1
# a=0
# b=0
# while b<100:
#     a=100-b
#     b=b+1
#     print(a)
# 15.购物车
# 功能要求：
# 要求用户输入总资产，比如：2000
# 显示商品列表，让用户根据序号选择商品，加入购物车。
# 购买，如果商品总额大于总资产，提示账户余额不足，否则购买成功。
goods = [
    {"name": "电脑", "price": 1999},
    {"name": "鼠标", "price": 10},
    {"name": "电灯", "price": 20},
    {"name": "椅子", "price": 899}]
inptotal = input("请输入持有金额：")
jici = 0
for good in goods:
    print(jici, good.get("name"))
    jici += 1
bool1 = True
buy = 0
while bool1:
    listgm = input("请输入购买物品的序号，如购买完成请输入ok开始付款")
    if listgm == "ok":
        if int(inptotal) - buy >= 0:
           print("购买成功,共付款：",buy)
           break
        else:
            print("购买失败,你还需要：",buy-int(inptotal))
            break
    else:
        if listgm.isdecimal() and int(listgm)<=len(goods):
            sp = goods[int(listgm)]
            buy = buy + sp.get("price")
        else:
            continue
二次修改

total = input("请输入所持有的总金额数：")
list_goods = {}
for k1, v1 in enumerate(goods, 1):
    list_goods.setdefault(k1, v1)
print(list_goods)
buy = 0
while True:
    xuhao = input("请输入要购买商品的序列号,输入ok结算：")
    if xuhao == "ok":
        break
    else:
        good = list_goods.get(int(xuhao),"none")
        if good=="none":
            print("无此商品，请重新选择。")
            continue
        sp = good.get("price")
        buy = buy + sp

if buy == 0:
    print("您什么也没有购买谢谢你的光临！")
elif buy > int(total):
    print("您所持有的金额不够支持本次购物")
elif buy < int(total):
    sy = int(total) -buy
    print("你已经购买成功，你还生剩余金额：", sy)
print("欢迎您下次再来！")