怎么一次抛出多个异常

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import java.util.ArrayList;
import java.util.List;

/**
 * 自定义异常
 */
public class MyException extends Exception {
    /**
     * 定义一个集合容纳异常
     */
    private List<Exception> exceptions = new ArrayList<>();

    public MyException(String message, List<Exception> exceptions) {
        super(message);
        this.exceptions = exceptions;
    }

    /**
     * 获取异常信息
     *
     * @return
     */
    public List<Exception> getExceptions() {
        return exceptions;
    }
}

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import java.util.ArrayList;
import java.util.List;

public class ThrowMoreException {
    /**
     * 假设是个注册的方法，入参就先省略了
     *
     * @return
     */
    public boolean reg() throws MyException {
        List<Exception> exceptions = new ArrayList<>();
        try {
            //假设调用业务会出现的异常
            throw new Exception("密码不能为空");
        } catch (Exception e) {
            exceptions.add(e);
        }

        try {
            //假设调用业务会出现的异常
            throw new Exception("用户名不能重复");
        } catch (Exception e) {
            exceptions.add(e);
        }

        try {
            //假设调用业务会出现的异常
            throw new Exception("邮箱非法");
        } catch (Exception e) {
            exceptions.add(e);
        }
        //如果确实有异常，那么就要抛出
        if (exceptions.size() > 0) {
            throw new MyException("注册异常", exceptions);
        }
        return true;
    }

    public static void main(String[] args) {
        try {
            new ThrowMoreException().reg();
        } catch (MyException e) {
            e.getExceptions().stream().forEach(System.out::println);
        }
    }
}