使用Easyx画任意三点组成的圆弧

代码如下

//使用三点画圆弧的函数
void circle_part(int left_x1, int left_y1, int middle_x2, int middle_y2, int right_x3, int right_y3)
{
	double middle_1_x, middle_1_y, middle_2_x, middle_2_y;
	double h1, h2;
	middle_1_x = (static_cast<double>(left_x1) + middle_x2) / 2;
	middle_1_y = (static_cast<double>(left_y1) + middle_y2) / 2;
	h1 = -(middle_x2 - left_x1) / (static_cast<double>(middle_y2) - left_y1) / 2;
	middle_2_x = (static_cast<double>(middle_x2) + right_x3) / 2;
	middle_2_y = (static_cast<double>(middle_y2) + right_y3) / 2;
	h2 = -(right_x3 - middle_x2) / static_cast<double>(2);
	int circle_center_x = (middle_2_y - middle_1_y + middle_1_x * h1 - middle_2_x * h2) / (h1 - h2);
	int circle_center_y = h1 * (circle_center_x - middle_1_x) + middle_1_y;
	int circle_radius = sqrt(pow((circle_center_x - left_x1), 2) + pow((circle_center_y - left_y1), 2));
	double atan2_1_y, atan2_1_x, atan2_2_y, atan2_2_x;
	atan2_1_y = right_y3 - circle_center_y;
	atan2_1_x = right_x3 - circle_center_x;
	atan2_2_y = left_y1 - circle_center_y;
	atan2_2_x = left_x1 - circle_center_x;
	int left, right, top, bottom;
	double stangle, endangle;
	left = circle_center_x - circle_radius;
	right = circle_center_x + circle_radius;
	top = circle_center_y - circle_radius;
	bottom = circle_center_y + circle_radius;
	stangle = atan2(atan2_1_y, atan2_1_x);
	endangle = atan2(atan2_2_y, atan2_2_x);
	arc(left, top, right, bottom, stangle, endangle);
}

最后

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