oracle命令窗口定义变量,在Oracle SQL Developer代码窗口中使用变量运行sql代码

我正在使用Oracle sql Developer编写代码.我有一个简单的选择语句工作：

SELECT

CFS.CAE_SEC_ID,CFS.FM_SEC_CODE,CFS.LAST_USER_ID,case

when 1 = 1 then

sl.usbank_to_edit

else

case

when 'ENTCB174' = CFS.last_user_id then

sl.owner_to_edit

else

sl.to_edit

end

end canEdit

FROM

CAEDBO.CAE_FOF_SECURITY CFS

INNER JOIN caedbo.CAE_DATA_SET_ELEMENT CDSE_STAT

ON (CDSE_STAT.DATA_SET_ELEMENT_ID = CFS.APPR_STATUS)

INNER JOIN caedbo.CAE_STATE_LOOKUP sl

ON (sl.object_state = CDSE_STAT.data_set_element_id)

where

cfs.CAE_SEC_ID in (3741,3744,3748,3752);

然而,我想添加一些变量,并引用语句中的变量,类似于下面,并在代码窗口中运行它.如何正确执行？

DECLARE

p_USBank_n NUMBER;

p_user_id_c VARCHAR2(20);

BEGIN

p_USBank_n := 1;

p_user_id_c := 'ENTCB174';

SELECT

CFS.CAE_SEC_ID,case

when p_USBank_n = 1 then

sl.usbank_to_edit

else

case

when p_user_id_c = CFS.last_user_id then

sl.owner_to_edit

else

sl.to_edit

end

end canEdit

FROM

CAEDBO.CAE_FOF_SECURITY CFS

INNER JOIN caedbo.CAE_DATA_SET_ELEMENT CDSE_STAT

ON (CDSE_STAT.DATA_SET_ELEMENT_ID = CFS.APPR_STATUS)

INNER JOIN caedbo.CAE_STATE_LOOKUP sl

ON (sl.object_state = CDSE_STAT.data_set_element_id)

where

cfs.CAE_SEC_ID in (3741,3752);

END;

当我在一个sql窗口中运行它,我得到以下消息：

Error report:

ORA-06550: line 8,column 5:

PLS-00428: an INTO clause is expected in this SELECT statement

06550. 00000 - "line %s,column %s:n%s"

*Cause: Usually a PL/sql compilation error.

*Action: