python 循环触发一次,python for循环仅执行一次？

import numpy as np

def Vin(t):

inputs = []

for i in range (1000):

if (-1)**(np.floor( 2 * t[i] )) == 1:

Vin = (1)

inputs.append(Vin)

else:

Vin = (-1)

inputs.append(Vin)

return inputs

when I use this function on a range of t values, I only get one result,

i.e.

input1=Vin(tpoints)

print (input1)

only gives [1], whereas I want the function to do it for every t value.

解决方案

You are returning from with in the for loop,So you would return from the function on first iteration of the loop.

you may re-writ e the function as following

Code

def Vin(t):

inputs = []

for i in range (1000):

if (-1)**(np.floor( 2 * t[i] )) == 1:

inputs.append(1)

else:

inputs.append(-1)

return inputs

Check the indentation of return inputs in the function here .

BTW, your function can be reduced to as more pythonic and efficient code

def Vin(t):

reduce map(lambda x:int((-1)**(np.floor( t[i] < 1))), range (1000))