BigInteger大整数类高精度

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我是靠谱客的博主安详月饼，最近开发中收集的这篇文章主要介绍BigInteger大整数类高精度，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

代码来自刘汝佳的《算法竞赛入门经典》（第二版）

#include <cstdio>
#include <cstring>
#include <vector>
#include <iostream>
#include <string>
#include <cmath>
#include <algorithm>
using namespace std;

struct BigInteger {
  static const int BASE = 100000000;
  static const int WIDTH = 8;
  vector<int> s;

  BigInteger(long long num = 0) { *this = num; } // 鏋勯€犲嚱鏁?
  BigInteger operator = (long long num) { // 璧嬪€艰繍绠楃
    s.clear();
    do {
      s.push_back(num % BASE);
      num /= BASE;
    } while(num > 0);
    return *this;
  }
  BigInteger operator = (const string& str) { // 璧嬪€艰繍绠楃
    s.clear();
    int x, len = (str.length() - 1) / WIDTH + 1;
    for(int i = 0; i < len; i++) {
      int end = str.length() - i*WIDTH;
      int start = max(0, end - WIDTH);
      sscanf(str.substr(start, end-start).c_str(), "%d", &x);
      s.push_back(x);
    }
    return *this;
  }
  BigInteger operator + (const BigInteger& b) const {
    BigInteger c;
    c.s.clear();
    for(int i = 0, g = 0; ; i++) {
      if(g == 0 && i >= s.size() && i >= b.s.size()) break;
      int x = g;
      if(i < s.size()) x += s[i];
      if(i < b.s.size()) x += b.s[i];
      c.s.push_back(x % BASE);
      g = x / BASE;
    }
    return c;
  }
};

ostream& operator << (ostream &out, const BigInteger& x) {
  out << x.s.back();
  for(int i = x.s.size()-2; i >= 0; i--) {
    char buf[20];
    sprintf(buf, "%08d", x.s[i]);
    for(int j = 0; j < strlen(buf); j++) out << buf[j];
  }
  return out;
}

istream& operator >> (istream &in, BigInteger& x) {
  string s;
  if(!(in >> s)) return in;
  x = s;
  return in;
}

#include <set>
#include <map>
set<BigInteger> s;
map<BigInteger, int> m;

int main() {
  BigInteger y;
  BigInteger x = y;
  BigInteger z = 123;

  BigInteger a, b;
  cin >> a >> b;
  cout << a + b << "n";
  cout << BigInteger::BASE << "n";
  system("pause");
  return 0;
}