用c语言编程井字游戏,用C语言编写的井字游戏源代码（井字三个级别）

井字游戏用C语言编写的源代码: //程序5. 8井字游戏#include int main(void){int player = 0;赢家= 0; int选择= 0; unsigned int行= 0; unsigned int colume = 0;字符板[3] [3] = {{'1'，'2'，'3'}，{'4'，'5'，'6'}，{'7'，'8'，'9' }}; //主游戏循环. 只要没有获胜者printf(“这是一个井字游戏，请尽情享受！”)，游戏将持续进行9圈. for(unsigned int i = 0; i <9 && Winner = = 0; ++ i){//显示白板printf(“ n”); printf(“％c |％c |％c n”，板[0] [0]，板[0] [1]，板[0] [2])； printf(“ --- + --- + --- n”); printf(“％c |％c |％c n”，board [1] [0]，board [1] [1]，板[1] [2])； printf(“ --- + --- + --- n”); printf(“％c |％c |％c n”，board [2] [0]，board [2] [1]，board [2] [2]);玩家= i％2 +1; //获取有效的玩家平方选择{printf(“玩家％d，请输入一个有效的平方数”“，将％c放置在哪里: ”玩家，(玩家== 1)？'X': 'O'); scanf(“％d”，＆choice); row = --choice / 3; colume =选择％3; } while(选择<0 ||选择> 8 || board [row] [colume]>'9')； //插入玩家symbleboard [row] [colume] =(player == 1)？'X': 'O'; //首先检查对角线是否是对角线if((board [0] [0] == board [1] [1] && board [0] [0] == board [2] [2])||( board [0] [2] == board [1] [1] && board [0] [2] == board [2] [0]))赢家=玩家；否则{//为(未签名的int行= 0；行<= 2; ++行){if((board [line] [0] == board [line] [1] &&板[线] [0] ==板[线] [2])||(板[0] [线] ==板[1] [线] &&板[0] [线] ==板[2] [line]))winner = player;}}} //游戏结束，因此显示最终的boardprintf(“ n”); printf(“％c |％c |％c n”，board [0] [0 ]用c语言编写游戏，板[0] [1]，板[0] [2])； printf(“ --- + --- + --- n”); printf(“％c |％c |％c n”，board [1] [0]，board [1] [1]， board [1] [2]); printf(“ --- + --- + --- n”); printf(“％c |％c |％c n”，board [2] [0]，board [2] [1]用c语言编写游戏，board [2] [2]); //显示结果消息if(winner)printf(“ n恭喜，玩家％d，您是赢家！ n”，赢家); else printf(“ n太无聊了，是平局 n”);返回0; }

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