概述
First of all, I understand that I can use global statement to access global variables. But somehow I was able to modify a global list without global like below:
def func1(nums):
nums = [4,5,6]
nums = [1,2,3]
func1(nums)
print nums # print [1,2,3]
def func2(nums):
nums[0] = 4
nums[1] = 5
nums[2] = 6
nums = [1,2,3]
func2(nums)
print nums # print [4,5,6]
After trying func2, I realized that I can always access global list in a function if I specify the index:
def func3(nums):
nums[:] = [4,5,6]
nums = [1,2,3]
func3(nums)
print nums # print [4,5,6]
Is it because Python automatically go trying to match a global variable if a function variable is used before definition?
Thanks.
解决方案I understand th
最后
以上就是洁净溪流为你收集整理的python定义全局列表_Python：修改函数内的全局列表的全部内容，希望文章能够帮你解决python定义全局列表_Python：修改函数内的全局列表所遇到的程序开发问题。
如果觉得靠谱客网站的内容还不错，欢迎将靠谱客网站推荐给程序员好友。
发表评论 取消回复