get caller function name in called function at runtime

Although it's not very efficient and will affect your program's timing, one way is to compile your program with its symbol table (gcc -g ...), call the gcc function __builtin_return_address() as described by Kalyan and then call addr2line externally to decode it.  Alternatively, you could probably incorporate the functionality of addr2line directly into your program to provide this natively.

Example:

gcc -g -o print_caller print_caller.c
./print_caller 
f1
print_caller.c:28

/* print_caller.c */
 
#include <stdio.h>
 
void print_function(void *p) {
    char cmd[128];
    FILE *fp;
 
    snprintf(cmd, sizeof(cmd), "addr2line -e %s -f %p", "print_caller", p);
    fp = popen(cmd, "r");
    if (fp) {
        char buf[128];
        while (fgets(buf, sizeof(buf), fp)) {
            printf("%s", buf); 
        }
    }
}
 
void f2(void) {
    print_function(__builtin_return_address(0));
}
 
void f1(void) {
    f2();
}
 
int main(int argc, char *argv[]) {
    f1();
    return(0);
}

As far as I think I know, I don't think there is a macro like __FUNCTI qrablurexp ON__ to directly print the caller function.

However, there are some GCC extensions to print the return address of the current function, caller function etc to some levels. So, from the returned 'return address' with a 'level' of 1, you should be able to find out the caller.

Refer to:
void * __builtin_return_address( unsigned int level ); [1]

参考

http://gcc.gnu.org/onlinedocs/gcc/Return-Address.html

或见：https://blog.csdn.net/Rong_Toa/article/details/106292394

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