方法一:回归实现
def PowerSetsRecursive(items): """Use recursive call to return all subsets of items, include empty set""" if len(items) == 0: #if the lsit is empty, return the empty list return [[]] subsets = [] first_elt = items[0] #first element rest_list = items[1:] #Strategy:Get all subsets of rest_list; for each of those subsets, a full subset list #will contain both the original subset as well as a version of the sebset that contains the first_elt for partial_sebset in PowerSetsRecursive(rest_list): subsets.append(partial_sebset) next_subset = partial_sebset[:] +[first_elt] subsets.append(next_subset) return subsets
def PowerSetsRecursive2(items): # the power set of the empty set has one element, the empty set result = [[]] for x in items: result.extend([subset + [x] for subset in result]) return result
方法二:二进制法def PowerSetsBinary(items): #generate all combination of N items N = len(items) #enumerate the 2**N possible combinations for i in range(2**N): combo = [] for j in range(N): #test jth bit of integer i if(i >> j ) % 2 == 1: combo.append(items[j]) yield combo
会陆续整理出其他的方法,当然,也欢迎在评论区留言。。。。。。
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