结构体数组和结构体的嵌套

结构体数组和结构体的嵌套

结构体数组

#include <stdio.h>
#include <string.h>

struct Student
{
	int age;
	char name[50];
	int score;
};


int main(int argc, char const *argv[])
{
	//结构体数组的初始化
	struct Student a[5] = 
	{
		{18, "mike", 59},
		{19, "jiang", 66},
		{33, "xiaobai", 82},
		{28, "lily", 77},
		{30, "xiaoan", 80}
	};

	int n = sizeof(a)/sizeof(a[0]);
	int sum = 0;
	for (int i = 0; i < n; ++i)
	{
		sum += a[i].score
	}

	printf("平均分：%dn", sum/n);
	return 0;
}


int main01(int argc, char const *argv[])
{
	struct Student a[5];//结构体数组

	//操作元素
	a[0].age = 18;
	strcpy(a[0].name, "mike");
	a[0].score = 59;

	//操作某个元素地址
	(a+1)->age = 19;
	strcpy((a+1)->name, "jiang");
	(a+1)->score = 60;

	//操作元素
	( *(a+2) ).age = 20;
	strcpy(( *(a+2)).name, "lily");
	( *(a+2)).score = 61;

	//用指针访问
	struct Student *p = a;
	p = &a[0];

	p[3].age = 21;
	strcpy(p[3].name, "xiaoming");
	p[3].score = 62;

	(p+4)->age = 22;
	strcpy((p+4)->name, "xiaojiang");
	(p+4)->score = 88;


	int i = 0;
	int n = sizeof(a)/sizeof(a[0]);
	for(i = 0; i < n; i++)
	{
		printf("%d, %s, %dn", a[i].age, a[i].name. a[i].score);
	}

	return 0;
}

结构体的嵌套

#include <stdio.h>
#include <string.h>

struct Info
{
	int age;
	char name[50];
}

struct Student
{
	struct Info info;
	int score;
};


int main(int argc, char const *argv[])
{
	struct Student s;
	s.info.age = 18;
	strcpy(s.info.name, "mike");
	s.score = 59;

	struct Student *p = &s;
	p->info.age = 18;
	strcpy(p->info.name, "mike");
	p->score = 59;

	struct Student tmp = {18, "mike", 59};
	printf("%d, %s, %dn", tmp.info.age, tmp.info.name, tmp.score);
	

	return 0;
}

最后

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