SQL中实现SPLIT函数几种方法总结(必看篇)

create function f_split(@SourceSql varchar(8000),@StrSeprate varchar(10))
returns @temp table(a varchar(100))
--实现split功能 的函数
--date :2003-10-14
as 
begin
declare @i int
set @SourceSql=rtrim(ltrim(@SourceSql))
set @i=charindex(@StrSeprate,@SourceSql)
while @i>=1
begin
insert @temp values(left(@SourceSql,@i-1))
set @SourceSql=substring(@SourceSql,@i+1,len(@SourceSql)-@i)
set @i=charindex(@StrSeprate,@SourceSql)
end
if @SourceSql<>'' 
insert @temp values(@SourceSql)
return 
end

select * from dbo.f_split('1,2,3,4',',')

a 
-------------------- 
1
2
3
4

（所影响的行数为 4 行）

--SQL Server Split函数
--Author:zc_0101 
--说明：
--支持分割符多字节
--使用方法 
--Select * FROM DBO.F_SQLSERVER_SPLIT('1203401230105045','0') 
--select * from DBO.F_SQLSERVER_SPLIT('abc1234a12348991234','1234') 
--Select * from DBO.F_SQLSERVER_SPLIT('ABC',',') 


CREATE FUNCTION F_SQLSERVER_SPLIT(@Long_str varchar(8000),@split_str varchar(100)) 
RETURNS @tmp TABLE( 
ID inT IDENTITY PRIMARY KEY, 
short_str varchar(8000) 
) 
AS 
BEGIN 
DECLARE @long_str_Tmp varchar(8000),@short_str varchar(8000),@split_str_length int 
SET @split_str_length = LEN(@split_str) 
IF CHARINDEX(@split_str,@Long_str)=1 
SET @long_str_Tmp=SUBSTRING(@Long_str,@split_str_length+1,LEN(@Long_str)-@split_str_length)
ELSE
SET @long_str_Tmp=@Long_str
IF CHARINDEX(REVERSE(@split_str),REVERSE(@long_str_Tmp))>1 
SET @long_str_Tmp=@long_str_Tmp+@split_str 
ELSE 
SET @long_str_Tmp=@long_str_Tmp 
IF CHARINDEX(@split_str,@long_str_Tmp)=0
Insert INTO @tmp select @long_str_Tmp 
ELSE
BEGIN
WHILE CHARINDEX(@spl(www.uoften.com)it_str,@long_str_Tmp)>0 
BEGIN 
SET @short_str=SUBSTRING(@long_str_Tmp,1,CHARINDEX(@split_str,@long_str_Tmp)-1) 
DECLARE @long_str_Tmp_LEN INT,@split_str_Position_END int 
SET @long_str_Tmp_LEN = LEN(@long_str_Tmp) 
SET @split_str_Position_END = LEN(@short_str)+@split_str_length 
SET @long_str_Tmp=REVERSE(SUBSTRING(REVERSE(@long_str_Tmp),1,@long_str_Tmp_LEN-@split_str_Position_END))
IF @short_str<>'' Insert INTO @tmp select @short_str 
END 
END
RETURN 
END

sql2000 
CREATE FUNCTION [dbo].[splitstring_array] 
( 
@string nvarchar(4000),@split char(1) 
) 

RETURNS @array table
( 
oneStr nvarchar(100) 
) 

AS

BEGIN
declare @v_code varchar(60) 

--zell 2006-05-26 
--set @string = replace(@string,' ',@split) 
--set @string = replace(@string,'，',@split) 

while len(@string) > 0 
begin
if charindex(@split,@string,1) != 0 
begin
set @v_code = substring(@string,1,charindex(@split,@string,1)-1) 
set @string = substring(@string,charindex(@split,@string,1)+1,len(@string)) 
end
else if charindex(@split,@string,1) = 0 
begin
set @v_code = @string 
set @string = ''
end
insert into @array(onestr) values(@v_code) 
end
RETURN
END

sql2005 
CREATE function [dbo].[func_splitid] 
(@str varchar(max),@split varchar(10)) 
RETURNS @t Table (c1 nvarchar(100)) 
AS
BEGIN
DECLARE @x XML 
SET @x = CONVERT(XML,'<items><item id="' + REPLACE(@str, @split, '"/><item id="') + '"/></items>') 
INSERT INTO @t SELECT x.item.value('@id[1]', 'nvarchar(100)') FROM @x.nodes('//items/item') AS x(item) 
RETURN 
END