一个判断email合法性的函数[非正则]

<%
Function IsValidEmail(email)
Dim names, Name, i, c
IsValidEmail = True
names = Split(email, "@")
If UBound(names) <> 1 Then
IsValidEmail = False
Exit Function
End If
For Each Name In names
If Len(Name) <= 0 Then
IsValidEmail = False
Exit Function
End If
For i = 1 To Len(Name)
c = LCase(Mid(Name, i, 1))
If InStr("abcdefghijklmnopqrstuvwxyz_-.", c) <= 0 And Not IsNumeric(c) Then
IsValidEmail = False
Exit Function
End If
Next
If Left(Name, 1) = "." Or Right(Name, 1) = "." Then
IsValidEmail = False
Exit Function
End If
Next
If InStr(names(1), ".") <= 0 Then
IsValidEmail = False
Exit Function
End If
i = Len(names(1)) - InStrRev(names(1), ".")
If i <> 2 And i <> 3 Then
IsValidEmail = False
Exit Function
End If
If InStr(email, "..") > 0 Then
IsValidEmail = False
End If
End Function
%>

最后

以上就是风趣指甲油为你收集整理的一个判断email合法性的函数[非正则]的全部内容，希望文章能够帮你解决一个判断email合法性的函数[非正则]所遇到的程序开发问题。

如果觉得靠谱客网站的内容还不错，欢迎将靠谱客网站推荐给程序员好友。