字符串综合练习

第一种解题思想
import java.util.Scanner;

public class exerCises {
    public static void main(String[] args) {
        String src;
        Scanner sr=new Scanner(System.in);
        while (true) {
            System.out.println("请输入一串数字");
           src=sr.next();
            boolean flag=check(src);
            if (flag)
            {
                 break;
            }else {
                System.out.println("不好意思你输入的字符串格式不对请重新输入");
                continue;
            }
        }
        StringBuilder sb=new StringBuilder();
        for (int i = 0; i <src.length() ; i++) {
            char b=src.charAt(i);
           int a=b-48;
           String s=luba(a);
           sb.append(s);

        }
        System.out.println(sb);

    }
    public static String luba(int sz)
    {
        String []arr={" ","Ⅰ","Ⅱ","Ⅲ","Ⅳ","Ⅴ","Ⅵ","Ⅶ","Ⅷ","Ⅸ"};
        return arr[sz];
    }
    public static boolean check(String src)
    {
        if(src.length()>=9)
        {
            return false;
        }
        for (int i = 0; i < src.length(); i++) {
            char ar=src.charAt(i);
            if (ar<'0'||ar>'9')
            {
                return false;
            }
        }
        return true;
    }
   
}

 第二种解题思路

 还有这一种jdk12以后的新特性

public class just {
    public static void main(String[] args) {
      String strA="abcde";
      String strB="bcdea";
      boolean result=cheak(strA,strB);
        System.out.println(result);

    }
    public static boolean cheak(String strA,String strB)
    {

        for (int i = 0; i <strA.length() ; i++) {
            strA=rotate(strA);
            if (strA.equals(strB))
            {
                return true;
            }
        }
        return false;
    }
    public static String rotate(String str)
    {
        char first=str.charAt(0);
        String end=str.substring(1);
        return end + first;
    }
}

最后

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