oracle练习题

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我是靠谱客的博主简单大树，最近开发中收集的这篇文章主要介绍oracle练习题，觉得挺不错的，现在分享给大家，希望可以做个参考。

概述

学生表

CREATE TABLE student(
sno VARCHAR(10) PRIMARY KEY,
sname VARCHAR(20),
sage NUMERIC(2),
ssex VARCHAR(5)
);

老师表
CREATE TABLE teacher(
tno VARCHAR(10) PRIMARY KEY,
tname VARCHAR(20)
);

课程表
CREATE TABLE course(
cno VARCHAR(10),
cname VARCHAR(20),
tno VARCHAR(20),
CONSTRAINT pk_course PRIMARY KEY (cno,tno)
);

分数表
CREATE TABLE sc(
sno VARCHAR(10),
cno VARCHAR(10),
score NUMERIC(4,2),
CONSTRAINT pk_sc PRIMARY KEY (sno,cno)
);
/*******初始化学生表的数据******/
insert into student values ('s001','张三',23,'男');
insert into student values ('s002','李四',23,'男');
insert into student values ('s003','吴鹏',25,'男');
insert into student values ('s004','琴沁',20,'女');
insert into student values ('s005','王丽',20,'女');
insert into student values ('s006','李波',21,'男');
insert into student values ('s007','刘玉',21,'男');
insert into student values ('s008','萧蓉',21,'女');
insert into student values ('s009','陈萧晓',23,'女');
insert into student values ('s010','陈美',22,'女');
commit;
/******************初始化教师表***********************/
insert into teacher values ('t001', '刘阳');
insert into teacher values ('t002', '谌燕');
insert into teacher values ('t003', '胡明星');
commit;
/***************初始化课程表****************************/
insert into course values ('c001','J2SE','t002');
insert into course values ('c002','Java Web','t002');
insert into course values ('c003','SSH','t001');
insert into course values ('c004','Oracle','t001');
insert into course values ('c005','SQL SERVER 2005','t003');
insert into course values ('c006','C#','t003');
insert into course values ('c007','JavaScript','t002');
insert into course values ('c008','DIV+CSS','t001');
insert into course values ('c009','PHP','t003');
insert into course values ('c010','EJB3.0','t002');
commit;
/***************初始化成绩表***********************/
insert into sc values ('s001','c001',78.9);
insert into sc values ('s002','c001',80.9);
insert into sc values ('s003','c001',81.9);
insert into sc values ('s004','c001',60.9);
insert into sc values ('s001','c002',82.9);
insert into sc values ('s002','c002',72.9);
insert into sc values ('s003','c002',81.9);
insert into sc values ('s001','c003','59');
commit;

1、查询“c001”课程比“c002”课程成绩高的所有学生的学号；
select c.*,d.*
from
(select*from sc a where a.cno = 'c001') c,
(select*from sc a where a.cno = 'c002') d
where c.score < d.score and c.sno = d.sno;
2、查询平均成绩大于60 分的同学的学号和平均成绩；
select avg(score),sno from sc group by sno having avg(score)>60;
3、查询所有同学的学号、姓名、选课数、总成绩；
select st.sno , st.sname , a.sum_score 总成绩,a.cno_count 选课数
from student st,
(select sum(score) sum_score, count(cno) cno_count,sno
from sc group by sno) a
where a.sno = st.sno;
4、查询姓“刘”的老师的个数
SELECT COUNT(tname) FROM teacher where tname like '刘%';
5、查询没学过“谌燕”老师课的同学的学号、姓名
select*from student
select * from student st where st.sno not in
(select distinct sno from sc s join course c on s.cno=c.cno
join teacher t on c.tno=t.tno where tname='谌燕');
6、查询学过“c001”并且也学过编号“c002”课程的同学的学号、姓名
select st.*
from sc a
join sc b on a.sno = b.sno
join student st on st.sno = a.sno
where a.cno = 'c001' and b.cno = 'c002' and st.sno = a.sno
7、查询学过“谌燕”老师所教的课的同学的学号、姓名；
select * from student st where st.sno in
(select distinct sno from sc s join course c on s.cno=c.cno
join teacher t on c.tno=t.tno where tname='谌燕');
8、查询课程编号“c002”的成绩比课程编号“c001”课程低的所有同学的学号、姓名；
select * from student st
join sc a on st.sno=a.sno
join sc b on st.sno=b.sno
where a.cno='c002' and b.cno='c001' and a.score < b.score

9、查询所有课程成绩小于60 分的同学的学号、姓名；
select st.*
from student st
join sc s on st.sno = s.sno
join course c on s.cno = c.cno
where s.score < 60;
10、查询至少有一门课与学号为“s001”的同学所学相同的同学的学号和姓名；
select st.*
from student st,
(select distinct a.sno from
(select*from sc) a,
(select*from sc where sc.sno = 's001') b
where a.cno = b.cno) h
where st.sno = h.sno and st.sno<>'s001';
11、把“SC”表中“谌燕”老师教的课的成绩都更改为此课程的平均成绩；
update sc sc1
   set sc1.score = (select avg(sc2.score)
                      from teacher t1, course c1, sc sc2
                     where c1.tno = t1.tno
                       and sc2.cno = c1.cno
                       and sc2.cno = sc1.cno
                       and t1.tname = '谌燕'
                     group by c1.cno)
where sc1.cno = (select c1.cno
                    from teacher t1, course c1
                   where c1.tno = t1.tno
                     and sc1.cno = c1.cno
                     and t1.tname = '谌燕') ;

12、查询和“s001”号的同学学习的课程完全相同的其他同学学号和姓名；

select* from sc where sno<>'s001'
minus
(
select* from sc
minus
select * from sc where sno='s001'
)
13、删除学习“谌燕”老师课的SC 表记录；
14、向SC 表中插入一些记录，这些记录要求符合以下条件：没有上过编号“c002”课程的同学学号、“c002”号课的平均成绩

15、查询各科成绩最高和最低的分：以如下形式显示：课程ID，最高分，最低分
select sc1.sno 课程 , max(sc1.score)最高分 , min(sc1.score) 最低分 from sc sc1 group by sc1.sno
select sc1.cno 课程 ,max(sc1.score) 最高分, min(sc1.score) 最低分
from sc sc1
group by sc1.cno;

16、按各科平均成绩从低到高和及格率的百分数从高到低顺序
select sc1.sno, avg(sc1.score) from sc sc1 group by sc1.sno order by avg(sc1.score)
17、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60]
select sc1.cno,c.cname,
sum(case when 85<sc1.score and sc1.score<= 100 then 1 else 0 end) 优秀,
sum(case when 70<sc1.score and sc1.score<= 85 then 1 else 0 end) 优良,
sum(case when 60<sc1.score and sc1.score<= 70 then 1 else 0 end) 中等,
sum(case when 0<sc1.score and sc1.score<= 60 then 1 else 0 end) 不及格
from sc sc1 , course c
where sc1.cno = c.cno
group by sc1.cno ,c.cname;
18、查询各科成绩前三名的记录:(不考虑成绩并列情况)
select*from sc a where (SELECT COUNT(*) FROM sc b where a.cno = b.cno and a.score < b.score)<3
order by a.cno,a.score desc
19、查询每门课程被选修的学生数
select sc1.cno ,count(sc1.sno)from sc sc1 group by sc1.cno
20、查询出只选修了一门课程的全部学生的学号和姓名
select st.sno,st.sname,count(sc1.cno)
from student st left join sc sc1 on st.sno = sc1.sno
group by st.sno,st.sname having count(sc1.cno) = 1;
21、查询男生、女生人数
select ssex, count(sno) from student group by ssex;
22、查询姓“张”的学生名单
select*from student where sname like'张%';
23、查询同名同性学生名单，并统计同名人数
select count(sno),sname from student group by sname having count(sno)>1

24、1997 年出生的学生名单(注：Student 表中Sage 列的类型是number)
select*from student where sage = (2020-1997)
25、查询每门课程的平均成绩，结果按平均成绩升序排列，平均成绩相同时，按课程号降序排列
select avg(sc1.score),sc1.cno
from sc sc1 group by sc1.cno
order by avg(sc1.score) asc,cno desc;
26、查询平均成绩大于85 的所有学生的学号、姓名和平均成绩

select st.sno,st.sname,avg(sc1.score)
from student st, sc sc1
where st.sno = sc1.sno(+)
group by st.sno ,st.sname having avg(sc1.score) >85
27、查询课程名称为“数据库”，且分数低于60 的学生姓名和分数
select st.sname,sc1.score
from student st, sc sc1,course co
where co.cname= 'Java Web' and co.cno = sc1.cno and sc1.sno = st.sno and sc1.score <60
28、查询所有学生的选课情况；
select st.sname,co.cname
from student st, sc sc1,course co
where co.cno = sc1.cno and sc1.sno = st.sno
29、查询任何一门课程成绩在70 分以上的姓名、课程名称和分数；
select st.sname,co.cname,sc1.score
from student st, sc sc1,course co
where co.cno = sc1.cno and sc1.sno = st.sno and sc1.score >70
30、查询不及格的课程，并按课程号从大到小排列
select sc.sno,c.cname,sc.score from sc,course c
where sc.cno=c.cno and sc.score<60 order by sc.cno desc;
31、查询课程编号为c001 且课程成绩在80 分以上的学生的学号和姓名；
select st.sname,co.cname,sc1.score
from student st, sc sc1,course co
where co.cno = sc1.cno and sc1.sno = st.sno and sc1.score >80 and sc1.cno = 'c001';
32、求选了课程的学生人数
SELECT COUNT(distinct cno) FROM sc
33、查询选修“谌燕”老师所授课程的学生中，成绩最高的学生姓名及其成绩
select st.sname,co.cname, max(sc1.score),sc1.cno,th.tname
from student st, sc sc1,course co,teacher th
where co.cno = sc1.cno and sc1.sno = st.sno and th.tno = co.tno and th.tname = '谌燕'
group by st.sname,co.cname ,sc1.cno,th.tname;

34、查询各个课程及相应的选修人
select sc1.cno,co.cname,count(sno)
from sc sc1 , course co
where sc1.cno = co.cno
group by sc1.cno,co.cname
35、查询不同课程成绩相同的学生的学号、课程号、学生成绩
select sc1.* from sc sc1, sc sc2 where sc1.score = sc2.score and sc1.cno <> sc2.cno;
36、查询每门功课成绩最好的前两名
select * from (
select sno,cno,score,row_number()over(partition by cno order by score desc) my_rn from sc t
)
where my_rn<=2