蓝桥杯VIP试题 之 基础练习 矩形面积交 - JAVA

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import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
	    Scanner sc = new Scanner(System.in);
	    //接收输入,分别存到两个数组中
	    double[] rectangle_1 = new double[4];
	    double[] rectangle_2 = new double[4];
	    for(int i = 0; i < rectangle_1.length; i++) {
	    	rectangle_1[i] = sc.nextDouble();
	    }
	    for(int j = 0; j < rectangle_2.length; j++) {
	    	rectangle_2[j] = sc.nextDouble();
	    }
	    
	    double X,Y;
	    //求相交矩形的长:X
	    double min_X = Math.min(Math.max(rectangle_1[0], rectangle_1[2]), Math.max(rectangle_2[0], rectangle_2[2]));
	    double max_X = Math.max(Math.min(rectangle_1[0], rectangle_1[2]), Math.min(rectangle_2[0], rectangle_2[2]));
	    X = min_X - max_X;
	    
	    //求相交矩形的宽:Y
	    double min_Y = Math.min(Math.max(rectangle_1[1], rectangle_1[3]), Math.max(rectangle_2[1], rectangle_2[3]));
	    double max_Y = Math.max(Math.min(rectangle_1[1], rectangle_1[3]), Math.min(rectangle_2[1], rectangle_2[3]));
	    Y = min_Y - max_Y;
	    
	    //若有一个是非正数,则两矩形是不想交的
	    if(X > 0 && Y > 0) {
	        double S = X * Y;
	        //保留两位小数并输出
	        System.out.println(String.format("%.2f", S));
	    }else {
	        System.out.println("0.00");
	    }
	}

}