概述
So what I want is a function that gets a tuple input from a user and then figures out if that tuple contains an even number. I want to know how to do it with a for or while loop. I've tried it but the code doesn't work. I've kind of got something but it's not working:
def ifEven(x):
i = -1
if isinstance(x, tuple):
while i < len(x):
for i in x:
i = i + 1
if x[i] % 2 == 0:
return True
else:
return False
解决方案
Here is a working code:
def ifEven(x):
if isinstance(x, tuple):
for i in x:
if i % 2 == 0:
return True
return False
That being said, it can be rewritten as a one-liner using Python's generator expressions:
def isEven(x):
return any(v % 2 == 0 for v in x)
最后
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