Python——保持字典的有序性

from random import randint
from collections import OrderedDict
from time import time

ordered_dict = OrderedDict()
players = list('ABCDEFGHI')
start_second = time()

for i in range(9) :
	input()
	p = players.pop(randint(0, 8-i))
	end_second = time()
	print(i+1, p, end_second - start_second)
	ordered_dict[p] = (i + 1, end_second - start_second)

print(ordered_dict)

运行结果：

OrderedDict([
('E', (1, 1.6347525119781494)), 
('A', (2, 2.6136345863342285)), 
('G', (3, 3.304358959197998)), 
('B', (4, 4.102595329284668)), 
('D', (5, 4.8459577560424805)), 
('H', (6, 5.447840213775635)),
('I', (7, 6.3935933113098145)), 
('C', (8, 7.570738315582275)), 
('F', (9, 8.239575147628784))])

最后

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