Codeforces刷题之路——266A Stones on the Table

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概述

There are n stones on the table in a row, each of them can be red, green or blue. Count the minimum number of stones to take from the table so that any two neighboring stones had different colors. Stones in a row are considered neighboring if there are no other stones between them.

Input

The first line contains integer n (1 ≤ n ≤ 50) — the number of stones on the table.

The next line contains string s, which represents the colors of the stones. We'll consider the stones in the row numbered from 1 to nfrom left to right. Then the i-th character s equals "R", if the i-th stone is red, "G", if it's green and "B", if it's blue.

Output

Print a single integer — the answer to the problem.

Examples

input
3
RRG

output
1

input
5
RRRRR

output
4

input
4
BRBG

output
0

题目大意：一排不同颜色的Stones，求解最少需要拿走几块stones才能够相邻的stones不同颜色。

解题思路：水题，暴力扫描。

以下为解题代码（java实现）

import java.util.Scanner;
public class Main {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
scanner.nextLine();
String str = scanner.nextLine();
char[] ch = str.toCharArray();
int counts = 0;
for(int i = 0;i < ch.length-1;i++){
if(ch[i] == ch[i+1]){
counts++;
}
}
System.out.println(counts);
scanner.close();
}
}