python标准日期正则表达式_Python 正则表达式验证传统日期

Pure regular exprssion

(?x)(?:

(?#dd/mm)

(3[0-1]|[12][0-9]|0?[0-9])/(1[0-2]|0?[1-9])

|

(?#mm/dd)

(1[0-2]|0?[1-9])/(3[0-1]|[12][0-9]|0?[0-9])

)

/

(?#yy or yyyy)

(?:[0-9]{2})?[0-9]{2}

Regex with procedural code

def dateCheck(sDate):

import re

daysinmonth = (31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31)

validdate = 0

match = re.search("^(?P[0-3]?[0-9])/(?P[0-3]?[0-9])/(?P[0-9]{4})$", sDate)

if match:

month = int(match.group("month"))

day = int(match.group("day"))

year = int(match.group("year"))

if year < 50:

year += 2000

if year < 100:

year += 1900

if month == 2 and year % 4 == 0 and (year % 100 != 0 or year % 400 == 0):

if day >= 1 and day <= 29:

validdate = 1

elif month >=1 and month <= 12:

if day >=1 and day <= daysinmonth[month-1]:

validdate = 1

if validdate == 0:

print 'date is invalid!' % sDate

else:

print 'date is valid!' % sDate

def main():

while 1:

sDate = raw_input("Please input date (format is mm/dd/yyyy, exit to quit): ")

if sDate == 'exit':

break

else:

dateCheck(sDate)

main()