memmove() memcpy()只是memmove()的一个子集memcpy()在执行内存重叠的情况下时，就会发生错误，而memmove()不会void *memmove(void *dest, const void *src, size_t count){ assert((dest!=0)&&(src!=0)); unsigned char *pdest =(char * )d C 2023-09-26 43 点赞 0 评论 65 浏览
